我试图做这样的事情：sample_generic.feature
Scenario:
* def result = call read('#(feature)') headers
我有另一个这样的功能文件：sample_caller.feature
Scenario:
* def result = call read('sample_generic.feature') {feature: 'classpath:common/example.feature'}
当我尝试这样做时，我收到错误：
com.intuit.karate.exception.KarateException:
/****/test-suite/src/test/java/example/common/#(feature) (No such file or directory)
at com.intuit.karate.Script.evalFeatureCall(Script.java:1647)
at com.intuit.karate.Script.call(Script.java:1579)
at com.intuit.karate.Script.evalKarateExpression(Script.java:228)
at com.intuit.karate.Script.evalKarateExpression(Script.java:170)
at com.intuit.karate.Script.assign(Script.java:598)
at com.intuit.karate.Script.assign(Script.java:524)
at com.intuit.karate.StepDefs.def(StepDefs.java:305)
at ✽.* def result = call read('classpath:common/sample_generic.feature') {feature: 'example.feature'}(/*****/test-suite/src/test/java/example/common/example.feature:12)
关于这种动态调用功能文件本身是否支持空手道的想法？谢谢
1 回答
没关系 . 我搞定了 . 而不是'＃（feature）'，如果我们只通过功能，它就会好起来 .
这有效！