我有一个新问题,我正在使用一个名为interpreter的类:
Interpreter.h
#ifndef INTERPRETER_H_
#define INTERPRETER_H_
#include <string>
#include <stdlib.h>
#include <stdio.h>
#include <iostream>
using namespace std;
class Interpreter {
public:
static Interpreter* getInstance();
typedef void (*fn)(int, int, int, int);
static fn opcodes[44];
static fn functions[43];
private:
Interpreter() {
opcodes[9] = addiu;
opcodes[3] = jal;
opcodes[8] = addi;
opcodes[4] = beq;
opcodes[43] = sw;
functions[32] = add;
functions[33] = addu;
functions[34] = sub;
functions[18] = mflo;
functions[26] = div;
functions[12] = syscall;
functions[8] = jr;
}
;
void addiu(int, int, int, int);
void addi(int, int, int, int);
void jal(int, int, int, int);
void beq(int, int, int, int);
void sw(int, int, int, int);
void add(int, int, int, int);
void addu(int, int, int, int);
void sub(int, int, int, int);
void mflo(int, int, int, int);
void div(int, int, int, int);
void syscall(int, int, int, int);
void jr(int, int, int, int);
static Interpreter* _instance;
};
#endif /* INTERPRETER_H_ */
Interpreter.cpp
#include "Interpreter.h"
Interpreter* Interpreter::_instance = NULL;
Interpreter* Interpreter::getInstance() {
if (_instance == NULL) {
_instance = new Interpreter();
}
return _instance;
}
void Interpreter::addiu(int rs, int rt, int rd, int shamt) {
}
void Interpreter::addi(int rs, int rt, int rd, int shamt) {
}
void Interpreter::jal(int rs, int rt, int rd, int shamt) {
}
void Interpreter::beq(int rs, int rt, int rd, int shamt) {
}
void Interpreter::sw(int rs, int rt, int rd, int shamt) {
}
void Interpreter::add(int rs, int rt, int rd, int shamt) {
}
void Interpreter::addu(int rs, int rt, int rd, int shamt) {
}
void Interpreter::sub(int rs, int rt, int rd, int shamt) {
}
void Interpreter::mflo(int rs, int rt, int rd, int shamt) {
}
void Interpreter::div(int rs, int rt, int rd, int shamt) {
}
void Interpreter::syscall(int rs, int rt, int rd, int shamt) {
}
void Interpreter::jr(int rs, int rt, int rd, int shamt) {
}
但是当我尝试将函数保存在数组操作码或函数中时,程序在.h文件中有错误,完全在私有构造函数Interpreter()中 .
错误是:
不能将'Interpreter :: addiu'从类型'void(Interpreter ::)(int,int,int,int)'转换为'Interpreter :: fn {aka void(*)(int,int,int,int)} “
谢谢你的帮助
1 回答
您不能指向具有普通函数指针的非静态成员函数 . 您需要使用成员函数指针: