我试图在数据帧中加入一列时间戳 . 时间戳的格式为0:00:00,我认为它们是字符串 . 我尝试使用 uber.dtypes()
但它一直返回错误:
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-4-b4120eada070> in <module>()
----> 1 uber.dtypes()
TypeError: 'Series' object is not callable
picture of dataframe for reference
uber["Time"].head().to_dict()
返回以下内容:
{0: '0:11:00', 1: '0:17:00', 2: '0:21:00', 3: '0:28:00', 4: '0:33:00'}
当我使用这些箱子和标签时:
bins = np.arange(0, 25, 1)
labels = [
"0:00-1:00",
"1:01-2:00",
"2:01-3:00",
"3:01-4:00",
"4:01-5:00",
"5:01-6:00",
"6:01-7:00",
"7:01-8:00",
"8:01-9:00",
"9:01-10:00",
"10:01-11:00",
"11:01-12:00",
"12:01-13:00",
"13:01-14:00",
"14:01-15:00",
"15:01-16:00",
"16:01-17:00",
"17:01-18:00",
"18:01-19:00",
"19:01-20:00",
"20:01-21:00",
"21:01-22:00",
"22:01-23:00",
"23:01-24:00"
]
uber["Hour"] = pd.cut(uber["Time"], bins, labels = labels)
我收到以下错误:
TypeError: '<' not supported between instances of 'int' and 'str'
如果我将箱子更改为:
bins = str(np.arange(0, 25, 1)
我收到此错误:
AxisError: axis -1 is out of bounds for array of dimension 0
我意识到我可以将这些转换为秒和我们pd.to_numeric()将列转换为整数以便它们可以被分箱,但我已经在文档中查看并且仍然不清楚如何使用datetime或time来做到这一点(我可以做很长的路,然后乘以秒和分钟) .
1)如何使用日期时间或时间将这些时间戳转换为秒?
2)有没有办法在不将时间戳转换为秒的情况下将它们分开?
我也尝试将uber [“Time”]中的值转换为datetime.time对象,然后在binning之前将它们插入新列[“Time Object”]:
for i in range(len(uber["Time"])):
uber.loc[i, "Time Object"] = datetime.datetime.strptime(uber.loc[i, "Time"], "%H:%M:%S").time()
如果我尝试使用[“Time Object”]列进行bin:
uber["Hour"] = pd.cut(uber["Time Object"], bins = 24, labels = labels)
然后我收到此错误:
TypeError: '<=' not supported between instances of 'datetime.time' and 'str'
如果我尝试使用[“Time Object”]列的小时进行bin:
uber [“Hour”] = pd.cut(uber [“Time Object”] . 小时,bins = 24,labels = labels)
我收到此错误:
AttributeError: 'Series' object has no attribute 'hour'
1 回答
您可以尝试花几分钟时间和垃圾桶
日期: