我正在研究python（版本3），并且你可能知道，其中一个练习是创建一个岩石剪刀蜥蜴spock游戏（rpsls）我需要从下面的if语句开始，然后修改代码包含循环并使用随机函数添加计算机播放器 . 我花了几天时间调整代码和google搜索的东西，但是我还没能在循环中修复中断 . 陷入困境，要求玩家一个无休止地输入，并且永远不会加载与player2的比较或完成回合 . 我意识到这是一种编码游戏的混乱方式，但我想尽可能保留格式 .
import random
print("")
print("**** Welcome to Rock Paper Scissors ****")
print("")
inputOK = False
player2choices = ['rock', 'paper', 'scissors', 'lizard', 'spock']
while inputOK == False:
stringPlayer1 = input("Player 1, choose: rock, paper, scissors, lizard, or spock: ")
stringPlayer2 = random.choice(player2choices)
if stringPlayer1 == stringPlayer2:
print("Tie: Both players chose:" +
stringPlayer1)
elif stringPlayer1 == 'scissors' and stringPlayer2 == 'paper':
print("Player 1 wins: scissors cuts paper.")
elif stringPlayer1 == 'paper' and stringPlayer2 == 'rock':
print("Player 1 wins: paper covers rock.")
elif stringPlayer1 == 'rock' and stringPlayer2 == 'lizard':
print("Player 1 wins: rock crushes lizard.")
elif stringPlayer1 == 'lizard' and stringPlayer2 == 'spock':
print("Player 1 wins: lizard poisons spock.")
elif stringPlayer1 == 'spock' and stringPlayer2 == 'scissors':
print("Player 1 wins: Spock smashes scissors.")
elif stringPlayer1 == 'scissors' and stringPlayer2 == 'lizard':
print("Player 1 wins: scissors decapitates lizard.")
elif stringPlayer1 == 'lizard' and stringPlayer2 == 'paper':
print("Player 1 wins: lizard eats paper.")
elif stringPlayer1 == 'paper' and stringPlayer2 == 'spock':
print("Player 1 wins: paper disproves Spock.")
elif stringPlayer1 == 'spock' and stringPlayer2 == 'rock':
print("Player 1 wins: Spock vaporizes rock.")
elif stringPlayer1 == 'rock' and stringPlayer2 == 'scissors':
print("Player 1 wins: rock crushes scissors.")
elif stringPlayer1 == 'paper' and stringPlayer2 == 'scissors':
print("Player 2 wins: scissors cuts paper.")
elif stringPlayer1 == 'rock' and stringPlayer2 == 'paper':
print("Player 2 wins: paper covers rock.")
elif stringPlayer1 == 'lizard' and stringPlayer2 == 'rock':
print("Player 2 wins: rock crushes lizard.")
elif stringPlayer1 == 'spock' and stringPlayer2 == 'lizard':
print("Player 2 wins: lizard poisons spock.")
elif stringPlayer1 == 'scissors' and stringPlayer2 == 'spock':
print("Player 2 wins: Spock smashes scissors.")
elif stringPlayer1 == 'lizard' and stringPlayer2 == 'scissors':
print("Player 2 wins: scissors decapitates lizard.")
elif stringPlayer1 == 'paper' and stringPlayer2 == 'lizard':
print("Player 2 wins: lizard eats paper.")
elif stringPlayer1 == 'spock' and stringPlayer2 == 'paper':
print("Player 2 wins: paper disproves Spock.")
elif stringPlayer1 == 'rock' and stringPlayer2 == 'spock':
print("Player 2 wins: Spock vaporizes rock.")
elif stringPlayer1 == 'scissors' and stringPlayer2 == 'rock':
print("Player 2 wins: rock crushes scissors.")
else:
inputOK = False
print("Error: Not a valid choice.")
quit = input("Do you want to quit? ")
if quit.lower() == "y" or quit.lower() == "yes":
done = True
2 回答
用户将陷入无限循环，除非在while循环中的某个位置通过设置
inputOK = True来更改条件 .在此之前，您需要确定有效输入的条件，例如用户输入是有效选择之一（
if stringPlayer1 in player1choices）：这应该至少可以修复破碎的循环并允许您更多地继续开发游戏 .
while循环将继续循环，直到您的变量inputOk等于True . 您的错误是当玩家想要结束游戏时，inputOK没有更新为True . 也许你的意思是将inputOk设置为True而不是完成？
quit = input("Do you want to quit? ") if quit.lower() == "y" or quit.lower() == "yes": inputOk = True编辑：同样如前所述，你必须在python中缩进 . 任何未在while语句下缩进的代码都不会循环 .