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如何在多个正则表达式之间进行匹配并在它们之间进行替换

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在用户提供的任何科学论文中，程序必须.....

  • 找到：

1.a - 数字引用，例如

这些方法不是从汇总文本中复制完整句子，而是压缩句子[1,4-6]，或者从头开始重新生成新句子[3] .

1.b - 论文末尾的APA参考文献以及authoe的名称年份 .

  • 将数字转换为APA，例如

这些方法不是从汇总的文本中复制完整的句子，而是压缩句子（Jing 2000; Knight and Marcu 2000; Sporleder and Lapata 2005; SteinbergerandJežek2006），或者从头开始重新生成句子（McKeown et al 1999） ） .

我认为正则表达式是：

"\[(\d.*?)\]"

用于数字引用 .

"\d+([\.]([\ ])(([\D*])*([\,]))*([\ ][\w][\.]))|[\d]{4}"

适用于APA引用风格 .

我的问题是如何在第一种模式中替换第二种模式？

javascript regex

1 回答

  • 1

    将String.prototype.replace()与回调函数一起使用，该函数将数字字符串（逗号分隔，可能是范围）拆分为数字数组 . 然后遍历数字并使用您的其他正则表达式来查找作者/年 . 然后加入这些字符串并将其返回以进行替换 .

    var string = `Instead of reproducing full sentences from the summarized text, these methods either compress the sentences [1, 4-6], or re-generate new sentences from scratch [3].
1. Jing, H.: Sentence Reduction for Automatic Text Summarization. In Proceedings of the 6th Applied Natural Language Processing Conference, Seattle, USA, 2000, pp. 310–315.
3. McKeown et al: Sentence Reduction for Automatic Text Summarization. In Proceedings of the 6th Applied Natural Language Processing Conference, Seattle, USA, 1999, pp. 310–315.
4. Knight and Marcu.: Sentence Reduction for Automatic Text Summarization. In Proceedings of the 6th Applied Natural Language Processing Conference, Seattle, USA, 2000, pp. 310–315.
5. Sporleder and Lapata: Sentence Reduction for Automatic Text Summarization. In Proceedings of the 6th Applied Natural Language Processing Conference, Seattle, USA, 2005, pp. 310–315.
6. Steinberger and Ježek: Sentence Reduction for Automatic Text Summarization. In Proceedings of the 6th Applied Natural Language Processing Conference, Seattle, USA, 2006, pp. 310–315.`;

string.replace(/\[(\d[^\]]*)\]/g, function(matches, reference) {
    var numbers = [],
        authors = [];

    reference.split(/,\s*/g).forEach(function(number) {
        if(number.indexOf('-') !== -1) {
            var range = number.split('-');
            for(var i = range[0]; i <= range[1]; i++) {
                numbers.push(i);
            }
        } else numbers.push(number);
    });

    numbers.forEach(function(number) {
        var regex = new RegExp(number + '\\. ([^:]+):.*?(\\d{4})'),
            matches = regex.exec(string);
        authors.push(matches[1] + ' ' + matches[2]);
    });

    return '(' + authors.join('; ') + ')';
});
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