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第一次使用C语言中的类：请求非类型成员

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我按照你们告诉我的内容编辑了这个 . 它一直到这一行和错误

cout <<“起始速度是”<< honda.getSpeed（）<< endl << endl

[错误]请求'honda'中的成员'getSpeed'，这是非类型'Car（int，std :: string，int）{aka Car（int，std :: basic_string，int）}'

#include <iostream>
#include <iomanip>
#include <string>
using namespace std;

class Car  {
private:
    int yearModel;
    string make;
    int speed;

public:
    Car(int carYearModel, string carMake, int carSpeed = 0) {
        yearModel = carYearModel;
        make = carMake;
        speed = carSpeed; 
    }

    void accelerate() {
        speed += 5;
    }

    void brake() {
        speed -= 5;
    }

    int getSpeed() {
        return speed; 
    }

    int getyearModel() {
        return yearModel;
    }

    string getMake() {
        return make; 
    }
 };

int main() {

int count, YearModel, speed, make;
string carMake;

cout <<  "What is the speed?";
cin  >>  speed;

cout << "What is the year of the model?";
cin  >> YearModel;

cout << "What is the make?";
cin  >> make;

Car honda(int carYearModel, string carMake, int carSpeed);

cout << "The starting speed is " << honda.getSpeed() << endl << endl;
cout << "The year and model is  " << honda.getyearModel() << endl << endl;
cout << "The make of the car is "  << honda.getMake() << endl << endl;

return 0;
}
c++ class object constructor

2 回答

  • 2

    您的getter方法不应该要求用户输入 .

    此外，它应该是汽车本田（carYearModel，carMake，carSpeed）;并且您需要为变量carYearModel，carMake`和carSpeed赋值，然后才能将它们用作方法参数 . 您可以从用户那里获取这些值 . 调用方法时不包括参数数据类型 . 您只在定义方法时才这样做 .

    #include <iostream>
#include <iomanip>
#include <string>
using namespace std;

class Car  {
    private:
        int yearModel;
        string make;
        int speed;

    public:
        Car(int carYearModel, string carMake, int carSpeed = 0) {
            yearModel = carYearModel;
            make = carMake;
            speed = carSpeed; 
        }

        void accelerate() {
            speed += 5;
        }

        void brake() {
            speed -= 5;
        }

        int getSpeed() {
            return this.speed; 
        }

        int getyearModel() {
            return this.yearModel;
        }

        string getMake() {
            return this.make; 
        }
};

int main() {

    int count, carYearModel, carSpeed;
    string carMake;

    cout <<  "What is the speed?";
    cin  >> carSpeed;

    cout << "What is the year of the model?";
    cin  >> carYearModel;

    cout << "What is the make?";
    cin  >> carMake;

    Car honda(carYearModel, carMake, carSpeed);

    cout << "The starting speed is " << honda.getSpeed() << endl << endl;
    cout << "The year and model is  " << honda.getyearModel() << endl << endl;
    cout << "The make of the car is "  << honda.getMake() << endl << endl;

    return 0;
}
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  • 1
    Car honda(int carYearModel, string carMake, int carSpeed);

    声明一个名为 honda 的函数，它接受三个参数返回一个 Car . 你需要的是：

    int carYearModel = 2015;    // Some value
string carMake =  "Honda";  // Makes sense to define honda
int carSpeed = 155;         // Some value

// Create an object of type Car
Car honda(carYearModel, carMake, carSpeed);
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