我正在Centos平台上工作一个共享库和应用程序[clang,llvm3.9.0和libc],并且库和应用程序都会重载它们自己的operator new和operator delete .
除1例外,一切正常 . 在调用std :: string的copy构造函数时总是调用应用程序端的 operator new :
这是senario:
std::string str1 ( "A very strange issue on CentOS using clang and libc++" ); //operator new of library side called.
std::string str2(str1); //operator new of application side called. WHY??
对于库侧调用两种情况下的operator delete .
以下是运行以下代码时的日志:
====================================================
operator new in shared library
operator new called Application side
operator delete in shared library
operator delete in shared library
====================================================
共享库侧操作员new和delete:
void * operator new ( size_t len ) throw ( std::bad_alloc )
{
printf("operator new in shared library\n");
void * mem = malloc( len );
if ( (mem == 0) && (len != 0) ) throw std::bad_alloc();
return mem;
}
void * operator new[] ( size_t len ) throw ( std::bad_alloc )
{
printf("operator new[] in shared library\n");
void * mem = malloc( len );
if ( (mem == 0) && (len != 0) ) throw std::bad_alloc();
return mem;
}
void operator delete ( void * ptr ) throw()
{
printf("operator delete in shared library\n");
if ( ptr != 0 ) free ( ptr );
}
void operator delete[] ( void * ptr ) throw()
{
printf("operator delete[] in shared library\n");
if ( ptr != 0 ) free ( ptr );
}
应用程序端操作员new和operator delete:
void * operator new ( size_t len ) throw ( std::bad_alloc )
{
void * mem = malloc ( len );
printf("operator new called Application side\n");
if ( (mem == 0) && (len != 0) ) throw std::bad_alloc();
return mem;
}
void * operator new[] ( size_t len ) throw ( std::bad_alloc )
{
void * mem = malloc ( len );
printf("operator new[] called Application side\n");
if ( (mem == 0) && (len != 0) ) throw std::bad_alloc();
return mem;
}
void operator delete ( void * ptr ) throw()
{
printf("operator delete[] called Application side\n");
if ( ptr != 0 )free ( ptr );
}
void operator delete[] ( void * ptr ) throw()
{
printf("operator delete[] called Application side\n");
if ( ptr != 0 ) free ( ptr );
}
请帮忙 .
1 回答
简短的回答:不要这样做 .
只有一个替代品
operator new
(好吧,有一堆口味,比如noexcept
和[]
等,但只有一种口味) .如果您有多个,那么 - 正如您所发现的那样 - 不清楚哪个被调用,并且您可以获得对new和delete的不匹配调用,这是对未定义行为的快速访问 .
我可以解释为什么你重新报告,但它与内联模板和外部模板有关,这并不重要 . 你有
operator new
的两个替换函数,这就是问题所在 .