我正在使用WSO2-AM-1.9.0,试图使用Consumer Key和Consumer Secrete生成Access令牌 . 使用CURL拨打电话时工作正常
curl -k -d "grant_type=password&username=testuser1&password=testUser1&scope=SANDBOX" -H "Content-Type:application/x-www-form-urlencoded" -H "Authorization:Basic ZXNuaHJTZmJmOW9XS28xTVM5UHJSZ1BacUU0YTpld040RGh1ZmsxYTNZbndVNU1uMVlGM3IwanNh" http://10.0.100.108:8280/token
但是在尝试使用Java时,它会返回403错误代码 . 代码是:
try
{
HttpClient client = new DefaultHttpClient();
HttpGet get = new HttpGet("http://10.0.100.108:8280/token");
HttpParams params=new BasicHttpParams();
get.addHeader("Authorization","Basic ZXNuaHJTZmJmOW9XS28xTVM5UHJSZ1BacUU0YTpld040RGh1ZmsxYTNZbndVNU1uMVlGM3IwanNh");
get.addHeader("content-type", "application/x-www-form-urlencoded");
params.setParameter("grant_type", "password");
params.setParameter("username", "testuser1");
params.setParameter("password", "testUser1");
params.setParameter("scope", "SANDBOX");
get.setParams(params);
HttpResponse response = client.execute(get);
BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
String line = "";
while ((line = rd.readLine()) != null) {
responseBody = responseBody +"\n"+line;
}
}
catch(Exception ex)
{
ex.printStackTrace();
}
错误:403状态报告运行时错误在API中找不到给定请求的匹配资源
任何有关此的帮助和信息表示赞赏 .
1 回答
您必须发送POST请求而不是GET . 使用,