如何在swift中以编程方式调用手势点击UIView-Java 学习之路

107

我有一个UIView，并且我添加了点击手势：

let tap = UITapGestureRecognizer(target: self, action: Selector("handleTap:"))
tap.delegate = self
myView.addGesture(tap)

我试图在testfile中以编程方式调用它 .

sendActionForEvent

我正在使用此功能，但它不起作用：

myView.sendActionForEvent(UIEvents.touchUpDown)

它显示发送到实例的无法识别的选择器 .

我怎么解决这个问题？

提前致谢

18 回答

只需注意 - 不要忘记在视图上启用交互：

let tap = UITapGestureRecognizer(target: self, action: #selector(handleTap))

view.addGestureRecognizer(tap)

// view.userInteractionEnabled = true

self.view.addSubview(view)

回复于 2024-04-24T13:44:21+08:00

我在swift上研究了Xcode 6.4 . 见下文 .

var view1: UIView!

func assignTapToView1() {          
  let tap = UITapGestureRecognizer(target: self, action: Selector("handleTap"))
  //  tap.delegate = self
  view1.addGestureRecognizer(tap)
  self.view .addSubview(view1)

...
}

func handleTap() {
 print("tap working")
 view1.removeFromSuperview()
 // view1.alpha = 0.1
}

回复于 2024-04-24T13:44:21+08:00

斯威夫特4

let tap = UITapGestureRecognizer(target: self, action: #selector(self.touchTapped(_:)))
    self.view.addGestureRecognizer(tap)

@objc func touchTapped(_ sender: UITapGestureRecognizer) {
}

回复于 2024-04-24T13:44:21+08:00

如果你想要Objective C代码如下，

UITapGestureRecognizer *gesRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleTap:)]; // Declare the Gesture.
gesRecognizer.delegate = self;
[yourView addGestureRecognizer:gesRecognizer]; // Add Gesture to your view.

// Declare the Gesture Recognizer handler method.

- (void)handleTap:(UITapGestureRecognizer *)gestureRecognizer{
   NSLog(@"Tapped");
}

或者你想要快速代码如下，

import UIKit
class ViewController: UIViewController {

    @IBOutlet weak var myView: UIView!

    override func viewDidLoad() {
        super.viewDidLoad()

        // Add tap gesture recognizer to view
        let tapGesture = UITapGestureRecognizer(target: self, action: Selector("handleTap:"))
        myView.addGestureRecognizer(tapGesture)
    }

    // this method is called when a tap is recognized
    func handleTap(sender: UITapGestureRecognizer) {

        print("tap")
    }
}

回复于 2024-04-24T13:44:21+08:00

3

您可以直接调用 handleTap 函数，而不是调用myView的UITapGestureRecognizer，

回复于 2024-04-24T13:44:21+08:00

对于 Swift 4 ：

let tap = UITapGestureRecognizer(target: self, action: #selector(self.handleTap(_:)))

view.addGestureRecognizer(tap)

view.isUserInteractionEnabled = true

self.view.addSubview(view)

// function which is triggered when handleTap is called
@objc func handleTap(_ sender: UITapGestureRecognizer) {
    print("Hello World")
}

在Swift 4中，你需要明确指出触发函数可以从Objective-C调用，所以你需要添加@objc你的handleTap函数 .

请参阅@Ali Beadle的回答：Swift 4 add gesture: override vs @objc

回复于 2024-04-24T13:44:21+08:00

137
您需要使用目标和操作初始化 UITapGestureRecognizer ，如下所示：
```
let tap = UITapGestureRecognizer(target: self, action: #selector(self.handleTap(_:)))
tap.delegate = self // This is not required
myView.addGestureRecognizer(tap)
```
然后，您应该实现处理程序，每次发生tap事件时都会调用该处理程序：
```
func handleTap(sender: UITapGestureRecognizer? = nil) {
    // handling code
}
```
因此，现在调用您的tap手势识别器事件处理程序就像调用方法一样简单：
```
handleTap()
```
回复于 2024-04-24T13:44:21+08:00

对于正在寻找 Swift 3 解决方案的人

let tap = UITapGestureRecognizer(target: self, action: #selector(self.handleTap(_:)))

view.addGestureRecognizer(tap)

view.isUserInteractionEnabled = true

self.view.addSubview(view)

// function which is triggered when handleTap is called
 func handleTap(_ sender: UITapGestureRecognizer) {
     print("Hello World")
  }

回复于 2024-04-24T13:44:21+08:00

STEP : 1

@IBOutlet var viewTap: UIView!

STEP : 2

var tapGesture = UITapGestureRecognizer()

STEP : 3

override func viewDidLoad() {
    super.viewDidLoad()
    // TAP Gesture
    tapGesture = UITapGestureRecognizer(target: self, action: #selector(ViewController.myviewTapped(_:)))
    tapGesture.numberOfTapsRequired = 1
    tapGesture.numberOfTouchesRequired = 1
    viewTap.addGestureRecognizer(tapGesture)
    viewTap.isUserInteractionEnabled = true
}

STEP : 4

func myviewTapped(_ sender: UITapGestureRecognizer) {

    if self.viewTap.backgroundColor == UIColor.yellow {
        self.viewTap.backgroundColor = UIColor.green
    }else{
        self.viewTap.backgroundColor = UIColor.yellow
    }
}

OUTPUT

enter image description here

回复于 2024-04-24T13:44:21+08:00

1
您需要使用目标和操作初始化UITapGestureRecognizer，如下所示：
```
let tap = UITapGestureRecognizer(target: self, action: "handleTap:")
tap.delegate = self
myView.addGestureRecognizer(tap)
```
然后，您应该实现处理程序，每次发生tap事件时都会调用该处理程序：
```
func handleTap(sender: UITapGestureRecognizer) {
  // handling code
}
```
回复于 2024-04-24T13:44:21+08:00

这是它在Swift 3中的工作方式：

@IBOutlet var myView: UIView!
override func viewDidLoad() {
    super.viewDidLoad()

    let tap = UITapGestureRecognizer(target: self, action:#selector(handleTap))

    myView.addGestureRecognizer(tap)
}

func handleTap() {
    print("tapped")
}

回复于 2024-04-24T13:44:21+08:00

实现轻击手势

let tap: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: "touchHappen") 
view.userInteractionEnabled = true
view.addGestureRecognizer(tap)

识别出水龙头时调用此功能 .

func touchHappen() {
    //Causes the view (or one of its embedded text fields) to resign the first responder status.
    self.view.endEditing(true)
}

Update for For Swift 3

let tap = UITapGestureRecognizer(target: self, action: #selector(self.touchHappen(_:)))
view.addGestureRecognizer(tap)
view.userInteractionEnabled = true

func touchHappen(_ sender: UITapGestureRecognizer) {
    print("Hello Museer")
}

回复于 2024-04-24T13:44:21+08:00

Swift 4

首先，创建UITapGestureRecognizer的对象

var tapGesture = UITapGestureRecognizer()

第二步是初始化UITapGestureReconizer . 启用用户交互，然后添加它 .

override func viewDidLoad() {
        super.viewDidLoad()
    tapGesture = UITapGestureRecognizer(target: self, action: #selector(YourViewController.myviewTapped(_:)))
            infosView.isUserInteractionEnabled = true
            infosView.addGestureRecognizer(tapGesture)
view.addSubview(infosView)
}

第三，创建一个方法

@objc func myviewTapped(_ recognizer: UIGestureRecognizer) {
                print("button is tapped")
            }

回复于 2024-04-24T13:44:21+08:00

我在Swift 2.2上研究了Xcode 7.3.1 . 见下文 .

func addTapGesture() {
    let tap = UITapGestureRecognizer(target: self, action: #selector(MyViewController.handleTap))
    tap.numberOfTapsRequired = 1
    self.myView.addGestureRecognizer(tap)
}

func handleTap() {
    // Your code here...
}

回复于 2024-04-24T13:44:21+08:00

xCode 9.3，Swift 4.0

class BaseVC: UIViewController, UIGestureRecognizerDelegate { 

      @IBOutlet weak var iView: UIView!

      override func viewDidLoad() {
          super.viewDidLoad()
          let clickUITapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(self.onSelect(_:)))
          clickUITapGestureRecognizer.delegate = self
          iView?.addGestureRecognizer(tap)
      }

      func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool {
          return true
      }


     @IBAction func onSelect(_ sender: Any) {

     }
}

回复于 2024-04-24T13:44:21+08:00

76
我想说明两点让我一直遇到问题 .
- 我在init上创建了Gesture Recognizer并将其存储在let属性中 . 显然，将此手势识别添加到视图不起作用 . 可能是在init期间传递给手势识别器的自身对象，未正确配置 .
- 不应将手势识别器添加到零帧的视图中 . 我使用零帧创建我的所有视图，然后使用autolayout调整它们的大小 . 必须在自动布局引擎调整视图大小之后添加手势识别器 . 所以我在viewDidAppear中添加了手势识别器，它们可以工作 .
回复于 2024-04-24T13:44:21+08:00

let tap = UITapGestureRecognizer(target: self, action: Selector("handleFrontTap:"))
    frontView.addGestureRecognizer(tap)

// Make sure this is not private
func handleFrontTap(gestureRecognizer: UITapGestureRecognizer) {
    print("tap working")
}

回复于 2024-04-24T13:44:21+08:00

尝试以下swift代码（在Xcode 6.3.1中测试）：

import UIKit

    class KEUITapGesture150427 : UIViewController {
      var _myTap: UITapGestureRecognizer?
      var _myView: UIView?

      override func viewDidLoad() {
        super.viewDidLoad()
        view.backgroundColor = UIColor.whiteColor();

        _myTap = UITapGestureRecognizer(target: self
, action: Selector("_myHandleTap:"))
        _myTap!.numberOfTapsRequired = 1

        _myView = UIView(frame: CGRectMake(100, 200, 100, 100))
        _myView!.backgroundColor=UIColor.blueColor()
        _myView!.layer.cornerRadius = 20
        _myView!.layer.borderWidth = 1
        _myView!.addGestureRecognizer(_myTap!)
        view.addSubview(_myView!)
      }

      func _myHandleTap(sender: UITapGestureRecognizer) {
        if sender.state == .Ended {
          println("_myHandleTap(sender.state == .Ended)")
          sender.view!.backgroundColor
          = UIColor(red: CGFloat(drand48()), green: CGFloat(drand48()), blue: CGFloat(drand48()), alpha: 1.0);
        }
      }
    }

请注意，您的目标可以是UIResponder的任何子类，请参阅（在Xcode 6.3.1中测试）：

import UIKit

    class MyTapTarget  : UIResponder {
      func _myHandleTap2(sender: UITapGestureRecognizer) {
        if sender.state == .Ended {
          println("_myHandleTap2(sender.state == .Ended)")
          sender.view!.backgroundColor
            = UIColor(red: CGFloat(drand48()), green: CGFloat(drand48()), blue: CGFloat(drand48()), alpha: 1.0);
        }
      }
    }

    class KEUITapGesture150427b : UIViewController {
      var _myTap: UITapGestureRecognizer?
      var _myView: UIView?
      var _myTapTarget: MyTapTarget?

      override func viewDidLoad() {
        super.viewDidLoad()
        view.backgroundColor = UIColor.whiteColor();

        _myTapTarget = MyTapTarget()
        _myTap = UITapGestureRecognizer(target: _myTapTarget!
, action: Selector("_myHandleTap2:"))
        _myTap!.numberOfTapsRequired = 1

        _myView = UIView(frame: CGRectMake(100, 200, 100, 100))
        _myView!.backgroundColor=UIColor.blueColor()
        _myView!.layer.cornerRadius = 20
        _myView!.layer.borderWidth = 1
        _myView!.addGestureRecognizer(_myTap!)
        view.addSubview(_myView!)
      }
    }

回复于 2024-04-24T13:44:21+08:00

如何在swift中以编程方式调用手势点击UIView

18 回答

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