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Laravel 4关系排序一对多计数急切加载

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不确定这是否可行 . 我可以对当前表格中的所有内容( Headers ,正文等)进行排序,但还没有想到将其排序到与之相关的表格中 . 我想根据他/她拥有DESC,ASC的歌曲总数来对艺术家进行排序 .

How can I dynamically sort the total number of songs from the artists?

管理员/艺术家?sortby =首歌曲和秩序= ASC

Screenshot

我的 table

艺术家:id,name,body,slug

歌曲:id,title,body,slug,hits,artist_id

在此之前我使用了控制器中的热切加载,Artist :: with('songs)...然后在视图中我可以在foreach循环中使用,计算($ artist-> songs)的总歌曲 . 然后我发现了一种更清洁的方式http://laravel.io/forum/05-03-2014-eloquent-get-count-relation

艺术家模型

public function songs()
    {
        return $this->hasMany('Song');
    }

public function songsCountRelation()
{
    return $this->hasOne('Song')->selectRaw('artist_id, count("id") as count')->groupBy('artist_id');
}

public function getSongsCountAttribute()
{
    return $this->songsCountRelation->count;
}

歌曲模型

public function artist()
{
    return $this->belongsTo('Artist');
}

调节器

public function index()
{
    // Sortby and order variables from url 
    $this->data['sortby'] = Input::get('sortby');
    $this->data['order'] = Input::get('order');

    // If the sortby and order exists in url, fetch the data and order it accordingly
    if ($this->data['sortby'] && $this->data['order'])
    {
        // Order the data based on keys from url
        $this->data['artists'] = Artist::with('songsCountRelation')->orderBy($this->data['sortby'], $this->data['order'])->get(['id', 'name', 'body', 'slug']);

    }
    else
    {
        $this->data['artists'] = Artist::with('songsCountRelation')->get(['id', 'name', 'body', 'slug']);
    }

    $this->layout->content = View::make('admin.artists.index', $this->data);
}

索引视图

<th>
    {{--Sort by slug--}}
    @if ($sortby == 'slug' && $order == 'asc')

        {{ link_to_route('admin.artists.index', 'Slug', ['sortby' => 'slug', 'order' => 'desc']) }}
    @else
        {{ link_to_route('admin.artists.index', 'Slug', ['sortby' => 'slug', 'order' => 'asc']) }}
    @endif
</th>
<th>
    {{--Sort by total songs--}}
    @if ($sortby == 'songs' && $order == 'asc')
        {{ link_to_route('admin.artists.index', 'Songs', ['sortby' => 'songs', 'order' => 'desc']) }}
    @else
        {{ link_to_route('admin.artists.index', 'Songs', ['sortby' => 'songs', 'order' => 'asc']) }}
    @endif
</th>
...¨
@foreach($artists as $artist)
    <tr>
...
        <td>{{ $artist->songsCount; }}</td>
...     
    </tr>

@endforeach

提前致谢!

1 回答

  • 0

    你必须加入这些表格 .

    Artist::join('songs', ...)
      ->orderByRaw('count(songs.*) asc')
      ->select('artists.*')
      ->get();
    

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