我有一个ListBox绑定到CustomerViewModel对象列表,每个对象都有两个依赖属性:
- 名称(字符串)
- 描述(字符串)
- IsVisible(bool)
(默认情况下,IsVisible属性为True,并通过CustomerViewModel上的ToggleVisibility命令反转)
我想在边框控件的右边显示名称和描述,当IsVisible属性为True时显示透明背景,当False时显示绿色 .
我的问题是下面的代码的DataTrigger部分不能按我想要的方式工作,因为当IsVisible被更改时不会触发Setter-part .
我究竟做错了什么?
这是我的代码:
<UserControl.Resources>
<Style x:Key="ListBoxStyle" TargetType="{x:Type ListBox}">
<Setter Property="Margin" Value="-1,-1,0,0" />
<Setter Property="BorderThickness" Value="0" />
<Setter Property="Background" Value="Transparent" />
<Setter Property="ItemContainerStyle" Value="{DynamicResource ListboxItemStyle}" />
<Setter Property="ScrollViewer.HorizontalScrollBarVisibility" Value="Disabled" />
</Style>
<Style x:Key="ListboxItemStyle" TargetType="{x:Type ListBoxItem}">
<Setter Property="Background" Value="Transparent" />
<Setter Property="FocusVisualStyle" Value="{x:Null}" />
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type ListBoxItem}">
<Grid>
<Border x:Name="border" Background="{TemplateBinding Background}" BorderBrush="#FFD4D6D5" BorderThickness="0,0,0,1">
<Grid Height="70" Margin="0,0,10,0">
<Grid.RowDefinitions>
<RowDefinition Height="10" />
<RowDefinition Height="Auto" />
<RowDefinition />
<RowDefinition Height="10" />
</Grid.RowDefinitions>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="Auto" />
<ColumnDefinition />
</Grid.ColumnDefinitions>
<Border x:Name="visibilityColumn" Grid.Row="0" Grid.Column="0" Grid.RowSpan="4" Background="Transparent" Width="4" Margin="0,0,4,0" />
<TextBlock x:Name="customerName" Grid.Row="1" Grid.Column="1" Foreground="#FF191919" FontWeight="Bold" Text="{Binding Name}" VerticalAlignment="Top" />
<TextBlock Grid.Row="2" Grid.Column="1" VerticalAlignment="Stretch" Text="{Binding Description}" TextWrapping="Wrap" Foreground="#FFB4B4B4" TextTrimming="CharacterEllipsis" />
</Grid>
<Border.ContextMenu>
<ContextMenu>
<MenuItem Header="Edit..." />
<MenuItem Header="Visible" IsCheckable="True" IsChecked="{Binding IsVisible}" Command="{Binding ToggleVisibility}"/>
</ContextMenu>
</Border.ContextMenu>
</Border>
</Grid>
<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="#FFEEEEEE" />
</Trigger>
<Trigger Property="IsSelected" Value="True">
<Setter Property="Background" Value="#FFF5F5F5" />
<Setter TargetName="customerName" Property="Foreground" Value="Green" />
</Trigger>
<DataTrigger Binding="{Binding IsVisible}" Value="False"> <!--If Value="True" the customerName Border shows up green!-->
<Setter Property="Background" Value="Green" />
</DataTrigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
</UserControl.Resources>
<ListBox Style="{StaticResource ListBoxStyle}" ItemsSource="{Binding CustomerViewModels}" />
UPDATED:
正如Goblin指出的那样,DataTrigger确实错过了TargetName = "visibilityColumn" .
然而 - “真正的”问题是,这一行:
<MenuItem Header="Visible" IsCheckable="True" IsChecked="{Binding IsVisible}" Command="{Binding ToggleVisibility}"/>
一个可检查的MenuItem在IsChecked属性上有一个TwoWay绑定模式,所以我实际上反转了IsVisiblity两次 - 通过数据绑定和通过ToggleVisibility命令......哎呀:)
1 回答
尝试切换这部分:
有了这部分:
我想你错过了setter中的TargetName属性 . (顺便提一下你的IsSelected-和IsMouseOver-trigger)
希望这可以帮助!