ASP.NET MVC3 AJAX.BeginForm AjaxOptions OnSuccess OnFailure问题

4 回答

• 4

  <script type="text/javascript">
          function OnSuccess() {
              alert('Success');
          }
          function OnFailure(ajaxContext) {
              var response = ajaxContext.get_response();
              var statusCode = response.get_statusCode();
              alert('Failure');
              Here you can do whatever you want with the div.
              $('#targetDiv').empty();
          }
      </script>
      <div id="targetDiv">
      @using (Ajax.BeginForm("Index", "Home", 
        new AjaxOptions 
             { 
               UpdateTargetId = "targetDiv",
               OnSuccess ="OnSuccess",
               OnFailure ="OnFailure" 
             })
        {
          ... 
        }
    </div>
  

  回复于 2024-05-14T10:23:48+08:00
• 18

  似乎在ASP.NET MVC 4中，事情发生了一些变化 . 我必须使用以下属性来读取响应和状态：

  ajaxContext.responseJSON
  ajaxContext.responseText
  ajaxContext.status
  ajaxContext.statusText
  

  回复于 2024-05-14T10:23:48+08:00
• 0

  根据官方MSDN网站：如果响应状态不在200范围内，则调用此函数 .

  AjaxOptions.OnFailure Property

  回复于 2024-05-14T10:23:48+08:00
• 3

  AjaxOptions中的OnFailure查找JavaScript函数

  <script>
      function onError(ajaxContext) {
          var response = ajaxContext.get_response();
          var statusCode = response.get_statusCode();
          alert("Error occured. Status code = " + statusCode);
      }
  </script>
  

  在HTML中写这个以在出现错误时获得警报 .

  <div id="updateDiv">
  @using (Ajax.BeginForm(new AjaxOptions { HttpMethod = "Post", InsertionMode = InsertionMode.Replace, UpdateTargetId = "updateDiv", OnFailure = "onError" })) 
  { 
    @*Your HTML form code goes here.*@
  }
  </div>
  

  回复于 2024-05-14T10:23:48+08:00