我有问题在按钮中运行任务问题是:无法从threading.task.task转换为系统操作我在按钮中标记了行
private async void BtnStart_Click(object sender, EventArgs e)
{
if (String.IsNullOrEmpty( txtProxy.Text) || lstviewcomp.Items.Count==0)
{
MessageBox.Show("Please uploads files");
return;
}
proxies = txtProxy.Text.Split('\n');
proxycount = proxies.Length;
foreach (string item in lstviewcomp.Items)
{
proxycount++;
if (proxyCounter> proxycount)
{
proxyCounter = 0;
}
ProxyInfo = proxies[proxyCounter].Split(',');
var result = await Task.Run( MainAsync("", "", "", "", "", "")).GetAwaiter().GetResult();// Problem in this line
// proxyCounter++;
}
}
public async Task MainAsync(string instausername,string pass,string proxyip,string proxyport,string proxyusername,string proxypass)
{
try
{
// create user session data and provide login details
var userSession = new UserSessionData
{
UserName = instausername,
Password = pass
};
// create proxy handeler
var httpHndler = new HttpClientHandler();
IWebProxy proxy = new WebProxy(proxyip,Convert.ToInt32(proxyport));
proxy.Credentials = new NetworkCredential(proxyusername, proxypass);
httpHndler.Proxy = proxy;
// create new InstaApi instance using Builder
_instaApi = new InstaApiBuilder()
.SetUser(userSession)
.UseHttpClientHandler(httpHndler)
.UseLogger(logger: new DebugFileLogger()) // use logger for requests and debug messages
.SetRequestDelay(TimeSpan.FromSeconds(1)) // set delay between requests
.Build();
// login
txtLog.Text = txtLog.Text + $"Logging in as {userSession.UserName}"+" At "+DateTime.Now+"\n";
var logInResult = await _instaApi.LoginAsync();
if (!logInResult.Succeeded)
{
txtLog.Text = txtLog.Text + $"Unable to login: {logInResult.Info.Message}" + " At " + DateTime.Now + "\n";
}
else
{
txtLog.Text = txtLog.Text + $"Logging in success : {userSession.UserName}" + " At " + DateTime.Now + "\n";
}
}
catch (Exception ex)
{
Console.WriteLine(ex);
}
finally
{
var logoutResult = Task.Run(() => _instaApi.LogoutAsync()).GetAwaiter().GetResult();
if (logoutResult.Succeeded) txtLog.Text = txtLog.Text + "Logout sucess \n";
}
return false;
}
2 回答
public async Task MainAsync
应该改为
public async Task<bool> MainAsync
而不是
var result = await Task.Run( MainAsync("", "", "", "", "", "")).GetAwaiter().GetResult();
您可以使用
var result = await MainAsync("", "", "", "", "", "");
您还需要在以下行中使用
async
:var logoutResult = Task.Run(() => _instaApi.LogoutAsync()).GetAwaiter().GetResult();
=>
var logoutResult = await _instaApi.LogoutAsync();
Task.Run
取Func<Task>
或Action
(当然你可以通过另外的CancellationToken
) . 因此,对于您的情况,您需要传递一个返回任务的函数,并且不会尝试等待void
(我希望您记得您不能等待void
) . 只需获得任务结果:您可以直接等待任务而不是上面的代码:
但是如果你想通过任务'结果异步地继续你的工作流,你的_455234应该返回一个
Task<bool>
,正如@Olexiy Sadovnikov回答中所指出的并等待返回的任务 .