我已经阅读了关于类似问题的多个SO答案,但无法理解为什么事情对我不起作用 . 我已经尝试了this,它确实按照接受的答案中的说明工作,但不适用于模拟事件 .
这是组件:
import React, { Component } from 'react';
export default class App extends Component {
render() {
return (
<div>
<button
onClick={this.handleClick}>
Click me
</button>
</div>
);
}
func1() {
console.log("In func1");
this.func2();
}
func2() {
console.log("In func2");
}
handleClick() {
console.log("handleClick");
}
}
以下是测试文件 . test1和test2通过,测试3和test4失败 .
import React from 'react';
import { shallow } from 'enzyme';
import App from 'components/App';
const handleClickSpy = jest.spyOn(App.prototype, 'handleClick');
const handleClickMock = jest.fn();
it('test 1 - call handleClick spy', () => {
let wrapper = shallow(<App/>);
wrapper.find('button').simulate('click');
expect(handleClickSpy).toBeCalled();
});
it('test 2 - call func2 mock', () => {
let wrapper = shallow(<App/>);
const func2Mock = jest.fn();
wrapper.instance().func2 = func2Mock;
// wrapper.update();
wrapper.instance().func1();
expect(func2Mock).toBeCalled();
});
it('test 3 - call handleClick mock - take 1', () => {
let wrapper = shallow(<App/>);
wrapper.find('button').simulate('click');
expect(handleClickMock).toBeCalled();
});
it('test 4 - call handleClick mock - take 2', () => {
let wrapper = shallow(<App/>);
const handleClickMock2 = jest.fn();
wrapper.instance().handleClick = handleClickMock2;
wrapper.update();
wrapper.find('button').simulate('click');
expect(handleClickMock2).toBeCalled();
});
console.log打印输出如下(这意味着test3和test4中的两个模拟都不起作用):
console.log src\components\App.js:25
handleClick
console.log src\components\App.js:16
In func1
console.log src\components\App.js:25
handleClick
console.log src\components\App.js:25
handleClick
1 回答
我在airbnb/enzyme #1081找到了答案
这两项工作: