如何通过castor生成的对象在XML中按属性值查找元素

1 回答

• 0

  Note: 我是EclipseLink JAXB (MOXy)领导，是JAXB（JSR-222）专家组的成员 .

  ---

  不确定Castor，但你可以用EclipseLink JAXB (MOXy)轻松完成 .

  Customer

  注意如何通过 @XmlPath 注释在映射上指定条件 [@name='address'] ：

  package blog.predicate;
  
  import java.util.List;
  
  import javax.xml.bind.annotation.XmlAccessType;
  import javax.xml.bind.annotation.XmlAccessorType;
  import javax.xml.bind.annotation.XmlRootElement;
  import javax.xml.bind.annotation.XmlType;
  
  import org.eclipse.persistence.oxm.annotations.XmlPath;
  
  @XmlRootElement(name="node")
  @XmlType(propOrder={"firstName", "lastName", "address", "phoneNumbers"})
  @XmlAccessorType(XmlAccessType.FIELD)
  public class Customer {
  
      @XmlPath("node[@name='first-name']/text()")
      private String firstName;
  
      @XmlPath("node[@name='last-name']/text()")
      private String lastName;
  
      @XmlPath("node[@name='address']")
      private Address address;
  
      @XmlPath("node[@name='phone-number']")
      private List<PhoneNumber> phoneNumbers;
  
  }
  

  XML

  <?xml version="1.0" encoding="UTF-8"?>
  <node>
     <node name="first-name">Jane</node>
     <node name="last-name">Doe</node>
     <node name="address">
        <node name="street">123 A Street</node>
     </node>
     <node name="phone-number" type="work">555-1111</node>
     <node name="phone-number" type="cell">555-2222</node>
  </node>
  

  For More Information

  • http://bdoughan.blogspot.com/2011/03/map-to-element-based-on-attribute-value.html

  回复于 2024-04-25T14:20:35+08:00