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选择具有不同where条件的相同列

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此查询返回特定日期范围内特定销售人员的“已结算”每日销售额总和：

SELECT SUM(price) as closed_total
 FROM   dbo.Sales
 WHERE  salesperson_ID = @salesperson_ID
        AND date_ordered BETWEEN @start_date AND @end_date
        AND closed = 1
 GROUP BY date_ordered

输出如下：

daily_total
200
150
325
120
(etc)

我想修改查询以返回一列用于已关闭的销售，一列用于所有销售（相同的查询，但没有'closed = 1'条件），输出如下：

closed_total | all_total
200          | 275
150          | 150
325          | 500
120          | 280
(etc)

我已经尝试使用UNION来组合单独的查询，如下所示：

SELECT SUM(price) as closed_total
 FROM   dbo.Sales
 WHERE  salesperson_ID = @salesperson_ID
        AND date_ordered BETWEEN @start_date AND @end_date
        AND closed = 1
 GROUP BY date_ordered
UNION ALL
 SELECT SUM(price) as all_total
 FROM   dbo.Sales
 WHERE  salesperson_ID = @salesperson_ID
        AND date_ordered BETWEEN @start_date AND @end_date
 GROUP BY date_ordered

我认为这可能会做我想要的，但它将两个总和放入一个名为'closed_total'的列中 . 有任何想法吗？

sql sql-server tsql aggregate-functions

1 回答

  • 13

    你可以试试这个

    SELECT SUM(price) as total, SUM(CASE WHEN closed = 1 THEN price ELSE 0 END) as closed_total
 FROM   dbo.Sales
 WHERE  salesperson_ID = @salesperson_ID
        AND date_ordered BETWEEN @start_date AND @end_date
 GROUP BY date_ordered
    回复于

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