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mysql关系慢

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<?php
$db = new mysqli(//editted out db credentials);

if($db->connect_errno > 0){
    die('Unable to connect to database [' . $db->connect_error . ']');
}
$sql = "SELECT m.ID, m.Title, GROUP_CONCAT(a.Title) AS Artist
FROM mp3s m
LEFT JOIN artist_relations ar ON ar.mp3ID = m.ID
LEFT JOIN artists a ON a.ID = ar.artistID
GROUP BY m.ID
ORDER BY ID
LIMIT 0,30;
";

if($result = $db->query($sql)){
echo "<table>";
while($row = $result->fetch_assoc()){
    echo "<tr>";  
    echo "<td>".$row['Title']."</td>";
    echo "<td>".$row['Artist']."</td>";
    echo "</tr>";  
}
echo "</table>";
}

?>

此查询工作正常,但速度非常慢 .

该数据库有3个字段:

`artists` : ID , Title
`mp3s` : ID , Title
`artist_relations` : mp3ID , artistID

我需要这个:

row1: titlemusic1 - artist1 , artist4 , artist5
row2: titlemusic2 - artist1
row3: titlemusic1 - artist3 , artist8
row4: titlemusic1 - artist9 , artist10
...

mp3s,artist&artist_relations每个都有超过20000条记录

EXPLAIN SELECT m.ID, m.Title, .... :
    id  select_type     table   type    possible_keys   key     key_len     ref     rows    Extra   
    1   SIMPLE  m   ALL     NULL    NULL    NULL    NULL    23718   Using temporary; Using filesort
    1   SIMPLE  ar  ALL     NULL    NULL    NULL    NULL    24337   
    1   SIMPLE  a   eq_ref  PRIMARY     PRIMARY     4   ganools_rj.ar.artistID  1

- 表artist_relations的表结构

CREATE TABLE IF NOT NOT EXISTS artist_relationsartistID int(11)NOT NULL, mp3ID int(11)NOT NULL)ENGINE = InnoDB DEFAULT CHARSET = latin1;


- 表格艺术家的表格结构

CREATE TABLE IF NOT NOT EXISTS artistsID int(11)NOT NULL AUTO_INCREMENT, Title varchar(155)NOT NULL PRIMARY KEY( ID ))ENGINE = InnoDB DEFAULT CHARSET = latin1 AUTO_INCREMENT = 9005;


- 表mp3的表结构

CREATE TABLE IF NOT NOT EXISTS mp3sID int(11)NOT NULL AUTO_INCREMENT, Title varchar(155)NOT NULL, imageURL varchar(155)NOT NULL, mp3URL varchar(155)NOT NULL, Description text, Lyric text, album varchar(155 )DEFAULT NULL, plays int(11)DEFAULT NULL, pubDate date NOT NULL,PRIMARY KEY( ID ))ENGINE = InnoDB DEFAULT CHARSET = latin1 AUTO_INCREMENT = 22936;


1 回答

  • 2

    尝试为artist_relations.mp3ID,artist_relations.artistID和mp3s.ID创建索引 . 见CREATE INDEX

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