猫鼬 - 通过Id找到孩子-Java 学习之路

详细信息：这是我的架构布局

Schema Layout:
const mongoose = require("mongoose");

module.exports = function(db) {

let gameSchema = new mongoose.Schema({

opponent: String,
location: String,
date: String,
completions: Number,
attempts: Number,
yards: Number,
touchdowns: Number,
interceptions: Number,
});

let quarterbackSchema = new mongoose.Schema({
firstName: String, 
lastName: String,
school: String,
age: Number,
hometown: String,
games:[gameSchema]
});

这是存储文档的样子

{
"_id": {
    "$oid": "5c0a551df8555c1c1ef0c101"
},
"firstName": "Pepper",
"lastName": "Princess ",
"age": 14,
"hometown": "Farmville, Ms",
"school": "Farmers School of Important Stuff",
"games": [
    {
        "_id": {
            "$oid": "5c0ca5ba7213fe6a5f52848c"
        },
        "opponent": "Crock McSnagglebite",
        "location": "Pattys Putrid Flower Garden",
        "date": "1/23/2020",
        "completions": 777,
        "attempts": 777,
        "yards": 777,
        "touchdowns": 777,
        "interceptions": 777
    }
],
"__v": 1
}

问题：我正在尝试通过_id找到子文档 . 我发布的示例代码将数字显示为“5c0ca5ba7213fe6a5f52848c” .

我试过了

Quarterback.find({_id: req.body.id}).then(function(Results){});

 Quarterback.findOne({_id: req.body.id}).then(ect...

 Quarterback.findById({_id: req.body.id}).then(ect...

以及许多其他方式，我根本不知道我做错了什么 . 我用了

JSON.stringify（req.body））;验证路线是否返回了我想要的值，它是
my console.log outputs the following

这是游戏细节req.body :: {“child”：“5c0d02649c936072d47f12a9”}

但是当使用上述方法时，find会继续为结果返回null . 我是一名学生，仍然在学习，所以也许我错过了一些简单的事情 . 我希望有人可以提供帮助 . 非常感谢您的参与！！

2 回答

0

您可以使用 mongoose populate 查找并显示id的子文档 . mongoose populate的链接：https://mongoosejs.com/docs/populate.html

回复于 2024-05-17T04:16:41+08:00
0
```
Quarterback.find({games._id: req.body.id}).then(function(Results){});
```
应该管用 . 您必须传递game._id，因为这是访问JSON对象和属性的方式
回复于 2024-05-17T04:16:41+08:00

猫鼬 - 通过Id找到孩子

2 回答

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