在Android上检索联系人图片

我目前正在开发一个Android项目，我试图在设备中查找联系电话号码并检索联系人信息，如联系人姓名和联系人图像 . 获取 Contract 名称工作正常，但是，在尝试获取照片uri时会抛出空指针 .

以下是我使用的代码：

public ContactInformation getContactInfoFromPhoneNumber(String number)
    {
        ContactInformation contactInformation = new ContactInformation();
        if (number == null)
        {
            return null;
        }
        number = number.replace(" ", "");

        if (number.startsWith("+"))
        {
            number = number.substring(3);
        }

        ContentResolver contentResolver = context.getContentResolver();

        Uri uri = ContactsContract.Data.CONTENT_URI;
        String[] projection = new String[] {ContactsContract.PhoneLookup._ID, ContactsContract.PhoneLookup.DISPLAY_NAME};
        String selection = "REPLACE (" + ContactsContract.CommonDataKinds.Phone.NUMBER + ", \" \" , \"\" ) LIKE ?";
        String[] selectionArgs = { "%" + number };
        Cursor cursor = contentResolver.query(uri, projection, selection, selectionArgs, null);

        if (cursor.moveToFirst())
        {
            contactInformation.contactName = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.PhoneLookup.DISPLAY_NAME));
            contactInformation.photoUri = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.PHOTO_URI));
            cursor.close();

            return contactInformation;
        }
        else
        {
            cursor.close();
            return null;
        }
    }

感谢您的任何帮助，您可以提供 .

UPDATE

以下是基于Itzik Samara答案的更新代码 .

以下是我如何进行联系人查询

public ContactInformation getContactInfoFromPhoneNumber(String number)
    {
        ContactInformation contactInformation = new ContactInformation();
        if (number == null)
        {
            return null;
        }
        number = number.replace(" ", "");

        if (number.startsWith("+"))
        {
            number = number.substring(3);
        }

        ContentResolver contentResolver = context.getContentResolver();

        Uri uri = ContactsContract.Data.CONTENT_URI;
        String[] projection = new String[] {ContactsContract.PhoneLookup._ID, ContactsContract.PhoneLookup.DISPLAY_NAME};
        String selection = "REPLACE (" + ContactsContract.CommonDataKinds.Phone.NUMBER + ", \" \" , \"\" ) LIKE ?";
        String[] selectionArgs = { "%" + number };
        Cursor cursor = contentResolver.query(uri, projection, selection, selectionArgs, null);

        if (cursor.moveToFirst())
        {
            contactInformation.contactName = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.PhoneLookup.DISPLAY_NAME));
            contactInformation.photoBase64String = getContactPhoto(cursor.getInt(cursor.getColumnIndexOrThrow(ContactsContract.Contacts._ID)));
            cursor.close();

            return contactInformation;
        }
        else
        {
            cursor.close();
            return null;
        }
    }

下面是我的getContactPhoto函数

private String getContactPhoto(int contactID)
    {
        Uri contactUri = ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, contactID);
        Uri photoUri = Uri.withAppendedPath(contactUri, ContactsContract.Contacts.Photo.CONTENT_DIRECTORY);
        Cursor cursor = context.getContentResolver().query(photoUri, new String[]{ContactsContract.Contacts.Photo.PHOTO},
                null, null, null);
        if (cursor == null)
        {
            return null;
        }
        if (cursor.getCount() > 0)
        {
            while (cursor.moveToNext()) {
                byte[] data = cursor.getBlob(0);
                String base64String = Base64.encodeToString(data, Base64.DEFAULT);
                cursor.close();
                return base64String;
            }
        }
        return null;
    }

它在if语句上失败并跳出if直接返回null，好像游标中没有任何内容 .