问题
我想要查询的是我的数据中每个“分组”的第二个结果 . 例如,带有星号的行 .
我试图在[Awardee],[State],[City]上分组,这应该是一个独特的人,我想获得他们最近的第二年[年] .
OFFSET函数可以解决问题,但MS ACCESS在其库中没有 . 我查找了使用嵌套查询 TOP n
的变通方法,但在使用变通方法时会产生更多问题 . 我可以使用某种类型的 JOIN
语句来完成此操作吗?
样本数据
------------------------------------
|_Awardee_|_State_|_City__|_Year___|
| John | OH | Cinci | 2015 |
*| John | OH | Cinci | 2013 |
| John | OH | Cinci | 2011 |
| Margret| IN | Indy | 2015 |
*| Margret| IN | Indy | 2012 |
| Margret| IN | Indy | 2011 |
| Bob | IN | Indy | 2011 |
*| Bob | IN | Indy | 2010 |
| Jeff | OH | Cinci | 2016 |
*| Jeff | OH | Cinci | 2015 |
| Jeff | OH | Cinci | 2013 |
| Jeff | OH | Cinci | 2012 |
| Susan | IN | Indy | 2012 |
| Spencer| IN | Indy | 2016 |
*| Spencer| IN | Indy | 2015 |
-------------------------------------
Example OFFSET workaround
通过按降序选择前2条记录,然后按升序选择前1条记录,我可以将结果偏移1 .
SELECT TOP 1 * FROM
(SELECT TOP 2 [Awardee], [State], [City], [Year] FROM [Table1]
ORDER BY [Awardee] ASC, [Year] DESC)
ORDER BY [Awardee] ASC, [Year] ASC;
工作SQL
这个SQL查询将获得他们最近的奖励年份(记录只有上面有一行astricks的1行) . 但是,正如我们可以看到我是否要使用上面的OFFSET解决方法替换子查询,我最终会得到2个子查询 . 最内部的子查询将无法在WHERE子句中重新标记“CDFI1” . MS ACCESS子查询无法看到最近的邻居查询 .
SELECT *
FROM [T09a: CDFI Award Records] AS CDFI1
WHERE CDFI1.[ID] IN
(SELECT TOP 1 ID FROM [T09a: CDFI Award Records] as CDFI2
WHERE CDFI2.[Awardee] = CDFI1.[Awardee] AND CDFI2.[City] = CDFI1.[City] AND CDFI2.[ST] = CDFI1.[ST]
ORDER BY CDFI2.[Awardee] ASC, CDFI2.[Year] DESC)
ORDER BY CDFI1.Awardee, CDFI1.Year DESC;
EDIT: Accepted Answer
感谢@krokodilko下面的演示和MYSQL帮助 . 为了在ACCESS中工作,有一些小的语法怪癖,主要是使用方括号,如下所示 .
SELECT t.[Awardee], t.[ST], t.[City], max( t.[Year] ) as Year
FROM ([T09a: CDFI Award Records] as t
INNER JOIN (
SELECT [Awardee], [ST], [City], max( [Year] ) as maxYear
FROM [T09a: CDFI Award Records]
GROUP BY Awardee, ST, City
) as x
ON x.Awardee = t.Awardee
AND x.[ST] = t.[ST]
AND x.[City] = t.[City]
AND t.[Year] < x.maxYear)
GROUP BY t.[Awardee], t.[ST], t.[City]
1 回答
我无权访问MS,
但是我会告诉你使用基本的SQL功能在MySql上做到这一点:JOIN GROUP BY MAX:
演示:http://sqlfiddle.com/#!9/690e47/7
我相信你会设法让它在MS Access上运行 .