我正在关注Spring Docs并配置 web.xml
和 applicatioinContext.xml
使用功能 Single root context in Spring Web MVC ,即没有Servlet WebApplicationContext;所有请求都将由Root WebApplicatioinContext提供 .
但问题是HTTP请求未被委托给根WebApplicationContext的控制器 .
web.xml:
<web-app>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/root-context.xml</param-value>
</context-param>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value></param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
</web-app>
root-context.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd">
<bean id="PostController" class="org.my.controllers.PostController">
</bean>
</beans>
Controller:
@Controller
public class PostController {
@RequestMapping(value= "/controller", method = RequestMethod.GET)
@ResponseBody
public String foo() {
return "Response!";
}
}
所以当我在浏览器中点击URL http://localhost:8080/PracticeJavaWeb/controller时,它显示404
Server log saying:
警告:在DispatcherServlet中找不到具有URI [/ PracticeJavaWeb / controller]的HTTP请求的映射,其名称为“dispatcher”
Spring Docs saying:
对于单个DispatcherServlet方案,也可以只有一个根上下文 .
2 回答
只需对root-context.xml文件进行一处小改动即可添加:
mvc:annotation-driven
使上下文路径能够识别spring mvc注释,以便将请求分派给控制器 .这里还有一个root-context.xml的完整示例
您需要在root-context.xml中添加
<mvc:annotation-driven />
标记 .<mvc:annotation-driven />
标记可确保将您的请求分派给控制器 .并且不要忘记在root-context.xml中添加mvc名称空间