我有一个呈现表单的ReactJS类,并根据输入状态启用/禁用“提交”按钮 . 如果填写了所有四个字段,则启用“提交”按钮,否则不启用 .
当我使用 React.DOM.Input
创建4个基本输入时,它工作正常,但是,当我从react-widgets添加一个React组件 DateTimePicker 时,我很难做到这一点 .
问题是,由于在选择日期后未调用 valid()
方法,因此永远不会启用“提交”按钮 .
见下面的代码:
DateTimePicker = require('react-widgets/lib/DateTimePicker');
momentLocalizer = require 'react-widgets/lib/localizers/moment'
momentLocalizer(require 'moment')
module.exports = React.createClass
getInitialState: ->
date: ''
project: ''
description: ''
duration: ''
handleChange: (e) ->
name = e.target.name
console.log(name);
console.log(e.target.value);
@setState "#{ name }": e.target.value
handleSubmit: (e) ->
e.preventDefault()
$.post '/tasks', { task: @state }, (data) =>
@props.handleNewTask data
@setState @getInitialState()
, 'JSON'
render: ->
dateChange = (date, dateStr) ->
name = "date"
@setState "#{ name }": dateStr
React.DOM.form
className: 'form-inline'
onSubmit: @handleSubmit
React.DOM.div
className: 'form-group'
React.createElement DateTimePicker,
time: false
name: 'date'
value: new Date(@state.date)
onChange: dateChange
React.DOM.div
className: 'form-group'
React.DOM.input
type: 'text'
className: 'form-control'
placeholder: 'Project'
name: 'project'
value: @state.project
onChange: @handleChange
React.DOM.div
className: 'form-group'
React.DOM.input
type: 'text'
className: 'form-control'
placeholder: 'Description'
name: 'description'
value: @state.description
onChange: @handleChange
React.DOM.div
className: 'form-group'
React.DOM.input
type: 'number'
className: 'form-control'
placeholder: 'Duration'
name: 'duration'
value: @state.duration
onChange: @handleChange
React.DOM.button
type: 'submit'
className: 'btn btn-primary'
disabled: !@valid()
'Add'
valid: ->
console.log @state
@state.date && @state.project && @state.description && @state.duration
1 回答
在您的代码中,
@setState
未引用组件setState
.this
关键字(咖啡中的@
)指的是函数所属的对象,或者窗口对象(如果它不属于任何对象) .在您的特定情况下,您应该将
dateChange
函数移出render
方法,并用onChange: @dateChange
替换onChange回调 . 这样,您将更新组件的实际状态,而不是render方法的成员 . 不要忘记在JavaScript中,函数是一个对象 .