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GUI必须等到启动画面完成执行

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我有一个SplashScreen类，它显示一个图像和一个进度条，直到初始化一些数据库 . 我希望在启动画面结束后打开一个新窗口 . 我有以下代码：

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public class Gui{

private static final String IMG_PATH = "../opt/images/splashscreendef.jpg";

public static void main(String[] args) throws ClassNotFoundException,
        InstantiationException, IllegalAccessException,
        UnsupportedLookAndFeelException {
    UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
    SwingUtilities.invokeLater(new Runnable() {
        public void run() {
            Gui ui = new Gui();
        }
    });
}

private inTouchGui() {
    InitSplashScreen splash = null;
    splash = new InitSplashScreen();
    try {
        splash.initUI();
    } catch (MalformedURLException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

    BufferedImage img = null;
    try {
        img = ImageIO.read(new File(IMG_PATH));
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    ImageIcon icon = new ImageIcon(img);
    JLabel label = new JLabel(icon);
    JOptionPane.showMessageDialog(null, label);
}

}

启动画面类

public class InitSplashScreen {
private JDialog dialog;
private JProgressBar progress;

public void initUI() throws MalformedURLException {
    showSplashScreen();
    SwingWorker<Void, Integer> worker = new SwingWorker<Void, Integer>(){

        @Override
        protected Void doInBackground() throws Exception {
            Thread thread = new Thread(new InitProcess());
            thread.start();
            int i = 0;
            while (thread.isAlive()){
                i++;
                Thread.sleep(200);// Loading of databases
                publish(i);// Notify progress
            }
            if (i < 10){
                for (i = 0; i < 100; i++){
                    Thread.sleep(50);// We simulate loading even if database is fully loaded
                    publish(i);// Notify progress
                }
            }
            return null;
        }

        @Override
        protected void process(List<Integer> chunks) {
            progress.setValue(chunks.get(chunks.size() - 1));
        }

        @Override
        protected void done() {
            hideSplashScreen();
        }

    };
    worker.execute();
}



protected void hideSplashScreen() {
    dialog.setVisible(false);
    dialog.dispose();
}

protected void showSplashScreen() throws MalformedURLException {
    dialog = new JDialog((Frame) null);
    dialog.setModal(false);
    dialog.setUndecorated(true);
    JLabel background = new JLabel(new ImageIcon("splashscreendef.jpg"));
    background.setLayout(new BorderLayout());
    dialog.add(background);
    progress = new JProgressBar();
    background.add(progress, BorderLayout.SOUTH);
    dialog.pack();
    dialog.setLocationRelativeTo(null);
    dialog.setVisible(true);
}

}

当我运行代码时，我同时获得启动画面和图像窗口，我试图使用 worker.get() ，但屏幕上没有任何内容 . 你能给我一些建议吗？我是Java Swing的新手 .

顺便说一句，例如，可能（可能意味着不是疯狂的代码加载和工作时间）来实现像这样的登录窗口吗？

http://designsparkle.com/wp-content/uploads/2014/06/a-simple-html-css-login-for.jpg

谢谢你的建议 .

java swing concurrency swingworker

1 回答

  • 2

    改变你的思维方式

    初始化并显示启动画面，当它完成时，初始化并显示 Gui

    这需要有一些方法来告诉谁曾经初始化它已经完成的启动画面，为此，你可以使用 PropertyChangeListener ...

    public class InitSplashScreen {
    //...
    public void initUI(PropertyChangeListener listener) throws MalformedURLException {
        showSplashScreen();
        SwingWorker<Void, Integer> worker = new SwingWorker<Void, Integer>() {
            //...
        };
        worker.addPropertyChangeListener(listener);
        worker.execute();
    }

    然后你监听 state change属性并检查工作状态......

    public static void main(String[] args) throws ClassNotFoundException,
                InstantiationException, IllegalAccessException,
                UnsupportedLookAndFeelException {
    UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
    SwingUtilities.invokeLater(new Runnable() {
        public void run() {
            InitSplashScreen splashScreen = new InitSplashScreen();
            try {
                splashScreen.initUI(new PropertyChangeListener() {
                    @Override
                    public void propertyChange(PropertyChangeEvent evt) {
                        String name = evt.getPropertyName();
                        if ("state".equalsIgnoreCase(name)) {
                            SwingWorker worker = (SwingWorker) evt.getSource();
                            if (worker.getState().equals(SwingWorker.StateValue.DONE)) {
                                Gui ui = new Gui();
                            }
                        }
                    }
                });
            } catch (MalformedURLException ex) {
                ex.printStackTrace();
            }
        }
    });
}

    但请记住，您需要从 Gui 代码中删除启动画面 .

    您也可以使用 Gui Gui Gui 中可能需要的任何信息，并将其作为参数传递给构造函数或根据您的需要通过setter

    另外，对我来说，这......

    Thread thread = new Thread(new InitProcess());
thread.start();

    在 SwingWoker 中看起来很奇怪 . 如果你不知道需要做多少工作，你可以简单地将 JProgressBar 留在indeterminate模式

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