如何在JavaScript中将字符串转换为日期？

var st = "date in some format"
var dt = new date();

var dt_st= //st in date format same as dt

30 回答

594

Date.parse 几乎可以得到你想要的东西 . 它在 am / pm 部分窒息，但有一些黑客你可以让它工作：

var str = 'Sun Apr 25, 2010 3:30pm',
    timestamp;

timestamp = Date.parse(str.replace(/[ap]m$/i, ''));

if(str.match(/pm$/i) >= 0) {
    timestamp += 12 * 60 * 60 * 1000;
}

回复于 2024-04-27T01:10:38+08:00

185
如果您可以使用极好的moment库（例如在Node.js项目中），您可以使用例如日期轻松解析日期 .
```
var momentDate = moment("2014-09-15 09:00:00");
```
并可以通过访问JS日期对象
```
momentDate ().toDate();
```
回复于 2024-04-27T01:10:38+08:00

时间戳应该转换为数字

var ts = '1471793029764';
ts = Number(ts); // cast it to a Number
var date = new Date(ts); // works

var invalidDate = new Date('1471793029764'); // does not work. Invalid Date

回复于 2024-04-27T01:10:38+08:00

10

看看datejs图书馆http://www.datejs.com/

回复于 2024-04-27T01:10:38+08:00
10

字符串解析的最佳字符串格式是日期ISO格式以及JavaScript Date对象构造函数 .

ISO格式的示例： YYYY-MM-DD 或 YYYY-MM-DDTHH:MM:SS .

But wait! 仅使用"ISO format"本身无法可靠地工作 . 字符串有时被解析为UTC，有时也被解析为本地时间（基于浏览器供应商和版本） . 最佳做法应始终是将日期存储为UTC并将计算结果作为UTC .

要将日期解析为UTC，请附加 Z - 例如： new Date('2011-04-11T10:20:30Z') .

要以UTC显示日期，请使用 .toUTCString() ，
要在用户的本地时间显示日期，请使用 .toString() .

有关MDN | Date和this answer的更多信息 .

对于旧的Internet Explorer兼容性（小于9的IE版本不支持Date构造函数中的ISO格式），您应该将日期时间字符串表示形式拆分为它的部分，然后您可以使用构造函数使用日期时间部分，例如： new Date('2011', '04' - 1, '11', '11', '51', '00') . 请注意，月份数必须少1 .

Alternate method - use an appropriate library:

您还可以利用库Moment.js，它允许使用指定的时区解析日期 .

回复于 2024-04-27T01:10:38+08:00

//little bit of code for Converting dates 

                var dat1 = document.getElementById('inputDate').value;
                var date1 = new Date(dat1)//converts string to date object
                alert(date1);
                var dat2 = document.getElementById('inputFinishDate').value;
                var date2 = new Date(dat2)
                alert(date2);

回复于 2024-04-27T01:10:38+08:00

使用此代码:(我的问题已通过此代码解决）

function dateDiff(date1, date2){
var diff = {}                           // Initialisation du retour
var tmp = date2 - date1;

tmp = Math.floor(tmp/1000);             // Nombre de secondes entre les 2 dates
diff.sec = tmp % 60;                    // Extraction du nombre de secondes

tmp = Math.floor((tmp-diff.sec)/60);    // Nombre de minutes (partie entière)
diff.min = tmp % 60;                    // Extraction du nombre de minutes

tmp = Math.floor((tmp-diff.min)/60);    // Nombre d'heures (entières)
diff.hour = tmp % 24;                   // Extraction du nombre d'heures

tmp = Math.floor((tmp-diff.hour)/24);   // Nombre de jours restants
diff.day = tmp;

return diff;

}

回复于 2024-04-27T01:10:38+08:00

68

只是 new Date(st);

假设它是正确的格式 .

回复于 2024-04-27T01:10:38+08:00

我使用此函数将任何Date对象转换为UTC Date对象 .

function dateToUTC(date) {
    return new Date(date.getUTCFullYear(), date.getUTCMonth(), date.getUTCDate(), date.getUTCHours(), date.getUTCMinutes(), date.getUTCSeconds());
}


dateToUTC(new Date());

回复于 2024-04-27T01:10:38+08:00

您可以使用正则表达式来解析字符串到详细时间，然后创建日期或任何返回格式，如：

//example : let dateString = "2018-08-17 01:02:03.4"

function strToDate(dateString){
    let reggie = /(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2}).(\d{1})/
  , [,year, month, day, hours, minutes, seconds, miliseconds] = reggie.exec(dateString)
  , dateObject = new Date(year, month-1, day, hours, minutes, seconds, miliseconds);
  return dateObject;
}
alert(strToDate(dateString));

回复于 2024-04-27T01:10:38+08:00

我已创建parseDateTime函数将字符串转换为日期对象，它在所有浏览器（包括IE浏览器）中工作，检查是否有人需要，参考https://github.com/Umesh-Markande/Parse-String-to-Date-in-all-browser

function parseDateTime(datetime) {
            var monthNames = [
                "January", "February", "March",
                "April", "May", "June", "July",
                "August", "September", "October",
                "November", "December"
              ];
            if(datetime.split(' ').length == 3){
                var date = datetime.split(' ')[0];
                var time = datetime.split(' ')[1].replace('.00','');
                var timearray = time.split(':');
                var hours = parseInt(time.split(':')[0]);
                var format = datetime.split(' ')[2];
                var bits = date.split(/\D/);
                date = new Date(bits[0], --bits[1], bits[2]); /* if you change format of datetime which is passed to this function, you need to change bits e.x ( bits[0], bits[1], bits[2 ]) position as per date, months and year it represent bits array.*/
                var day = date.getDate();
                var monthIndex = date.getMonth();
                var year = date.getFullYear();
                if ((format === 'PM' || format === 'pm') && hours !== 12) {
                    hours += 12;
                    try{  time = hours+':'+timearray[1]+':'+timearray[2] }catch(e){ time = hours+':'+timearray[1] }
                } 
                var formateddatetime = new Date(monthNames[monthIndex] + ' ' + day + '  ' + year + ' ' + time);
                return formateddatetime;
            }else if(datetime.split(' ').length == 2){
                var date = datetime.split(' ')[0];
                var time = datetime.split(' ')[1];
                var bits = date.split(/\D/);
                var datetimevalue = new Date(bits[0], --bits[1], bits[2]); /* if you change format of datetime which is passed to this function, you need to change bits e.x ( bits[0], bits[1], bits[2 ]) position as per date, months and year it represent bits array.*/
                var day = datetimevalue.getDate();
                var monthIndex = datetimevalue.getMonth();
                var year = datetimevalue.getFullYear();
                var formateddatetime = new Date(monthNames[monthIndex] + ' ' + day + '  ' + year + ' ' + time);
                return formateddatetime;
            }else if(datetime != ''){
                var bits = datetime.split(/\D/);
                var date = new Date(bits[0], --bits[1], bits[2]); /* if you change format of datetime which is passed to this function, you need to change bits e.x ( bits[0], bits[1], bits[2 ]) position as per date, months and year it represent bits array.*/
                return date;
            }
            return datetime;
        }

    var date1 = '2018-05-14 05:04:22 AM';   // yyyy-mm-dd hh:mm:ss A
    var date2 = '2018/05/14 05:04:22 AM';   // yyyy/mm/dd hh:mm:ss A
    var date3 = '2018/05/04';   // yyyy/mm/dd
    var date4 = '2018-05-04';   // yyyy-mm-dd
    var date5 = '2018-05-14 15:04:22';   // yyyy-mm-dd HH:mm:ss
    var date6 = '2018/05/14 14:04:22';   // yyyy/mm/dd HH:mm:ss

    console.log(parseDateTime(date1))
    console.log(parseDateTime(date2))
    console.log(parseDateTime(date3))
    console.log(parseDateTime(date4))
    console.log(parseDateTime(date5))
    console.log(parseDateTime(date6))

**Output---**
Mon May 14 2018 05:04:22 GMT+0530 (India Standard Time)
Mon May 14 2018 05:04:22 GMT+0530 (India Standard Time)
Fri May 04 2018 00:00:00 GMT+0530 (India Standard Time)
Fri May 04 2018 00:00:00 GMT+0530 (India Standard Time)
Mon May 14 2018 15:04:22 GMT+0530 (India Standard Time)
Mon May 14 2018 14:04:22 GMT+0530 (India Standard Time)

回复于 2024-04-27T01:10:38+08:00

对于在js中сonverting字符串到日期我使用 http://momentjs.com/

moment().format('MMMM Do YYYY, h:mm:ss a'); // August 16th 2015, 4:17:24 pm
moment().format('dddd');                    // Sunday
moment().format("MMM Do YY");               // Aug 16th 15
moment().format('YYYY [escaped] YYYY');     // 2015 escaped 2015
moment("20111031", "YYYYMMDD").fromNow(); // 4 years ago
moment("20120620", "YYYYMMDD").fromNow(); // 3 years ago
moment().startOf('day').fromNow();        // 16 hours ago
moment().endOf('day').fromNow();          // in 8 hours

回复于 2024-04-27T01:10:38+08:00

0
```
var date = new Date(year, month, day);
```
要么
```
var date = new Date('01/01/1970');
```
格式为'01 -01-1970'的日期字符串在FireFox中不起作用，因此最好在日期格式字符串中使用“/”而不是“ - ” .
回复于 2024-04-27T01:10:38+08:00

你应该做 own function . 这将更多 convenient . 这是一个例子 . 您可以根据您的要求进行修改 .

const  dateFormater = function(dt, seprator){

        let monthStore = ["January","February","March","April","May","June", "July","August","September","October","November","December"];
        

        const date = dt.split(seprator);
        //below choose month, day, year in the same order you passed in function as string
        const month = monthStore[date[0]-1]; 
        const day = date[1];
        const year = date[2];
        const dateToReturn = month+' '+day+' '+year // you can change order to print as required

        return(dateToReturn)
    }

var formatedDate = dateFormater('12/11/2018','/'); // /m/d/y
var formatedDate2 = dateFormater('09-10-2018','-');

console.log(formatedDate);
console.log(formatedDate2 )

回复于 2024-04-27T01:10:38+08:00

0

ISO 8601-esque datetrings，与标准一样出色，仍未得到广泛支持 .

这是一个很好的资源，可以确定您应该使用哪种日期字符串格式：

http://dygraphs.com/date-formats.html

是的，这意味着你的日期字符串可以简单到与之相反

"2014/10/13 23:57:52" 而不是 "2014-10-13 23:57:52"

回复于 2024-04-27T01:10:38+08:00

不幸的是我发现了

var mydate = new Date('2014-04-03');
console.log(mydate.toDateString());

返回“2014年4月2日星期三” . 我知道这听起来很疯狂，但有些用户会发生这种情况 .

bulletproof solution 如下：

var parts ='2014-04-03'.split('-');
// Please pay attention to the month (parts[1]); JavaScript counts months from 0:
// January - 0, February - 1, etc.
var mydate = new Date(parts[0], parts[1] - 1, parts[2]); 
console.log(mydate.toDateString());

回复于 2024-04-27T01:10:38+08:00

如果在转换为Date格式之前需要检查字符串的内容：

// Convert 'M/D/YY' to Date()
mdyToDate = function(mdy) {
  var d = mdy.split(/[\/\-\.]/, 3);

  if (d.length != 3) return null;

  // Check if date is valid
  var mon = parseInt(d[0]), 
      day = parseInt(d[1]),
      year= parseInt(d[2]);
  if (d[2].length == 2) year += 2000;
  if (day <= 31 && mon <= 12 && year >= 2015)
    return new Date(year, mon - 1, day);

  return null; 
}

回复于 2024-04-27T01:10:38+08:00

102

你也可以这样做：mydate.toLocaleDateString（）;

回复于 2024-04-27T01:10:38+08:00

对于那些正在寻找一个小巧聪明的解决方案的人：

String.prototype.toDate = function(format)
{
  var normalized      = this.replace(/[^a-zA-Z0-9]/g, '-');
  var normalizedFormat= format.toLowerCase().replace(/[^a-zA-Z0-9]/g, '-');
  var formatItems     = normalizedFormat.split('-');
  var dateItems       = normalized.split('-');

  var monthIndex  = formatItems.indexOf("mm");
  var dayIndex    = formatItems.indexOf("dd");
  var yearIndex   = formatItems.indexOf("yyyy");
  var hourIndex     = formatItems.indexOf("hh");
  var minutesIndex  = formatItems.indexOf("ii");
  var secondsIndex  = formatItems.indexOf("ss");

  var today = new Date();

  var year  = yearIndex>-1  ? dateItems[yearIndex]    : today.getFullYear();
  var month = monthIndex>-1 ? dateItems[monthIndex]-1 : today.getMonth()-1;
  var day   = dayIndex>-1   ? dateItems[dayIndex]     : today.getDate();

  var hour    = hourIndex>-1      ? dateItems[hourIndex]    : today.getHours();
  var minute  = minutesIndex>-1   ? dateItems[minutesIndex] : today.getMinutes();
  var second  = secondsIndex>-1   ? dateItems[secondsIndex] : today.getSeconds();

  return new Date(year,month,day,hour,minute,second);
};

例：

"22/03/2016 14:03:01".toDate("dd/mm/yyyy hh:ii:ss");
"2016-03-29 18:30:00".toDate("yyyy-mm-dd hh:ii:ss");

回复于 2024-04-27T01:10:38+08:00

-3

new Date(2000, 10, 1) 会给你"Wed Nov 01 2000 00:00:00 GMT+0100 (CET)"

看到0月份给你一月

回复于 2024-04-27T01:10:38+08:00

如果你想转换格式“dd / MM / yyyy” . 这是一个例子：

var pattern = /^(\d{1,2})\/(\d{1,2})\/(\d{4})$/;
var arrayDate = stringDate.match(pattern);
var dt = new Date(arrayDate[3], arrayDate[2] - 1, arrayDate[1]);

此解决方案适用于小于9的IE版本 .

回复于 2024-04-27T01:10:38+08:00

9
moment.js（http://momentjs.com/）是一个完整而优秀的使用日期包，并支持ISO 8601 strings .

您可以添加字符串日期和格式 .
```
moment("12-25-1995", "MM-DD-YYYY");
```
你可以检查一个日期是否有效 .
```
moment("not a real date").isValid(); //Returns false
```
见文档http://momentjs.com/docs/#/parsing/string-format/

建议：我建议使用包含很多格式的日期，因为时区和格式时间管理确实是一个大问题，时刻js解决了很多格式 . 您可以轻松地从简单的字符串中解析日期，但我认为这是支持所有格式和日期变体的艰苦工作 .
回复于 2024-04-27T01:10:38+08:00

function stringToDate(_date,_format,_delimiter)
{
            var formatLowerCase=_format.toLowerCase();
            var formatItems=formatLowerCase.split(_delimiter);
            var dateItems=_date.split(_delimiter);
            var monthIndex=formatItems.indexOf("mm");
            var dayIndex=formatItems.indexOf("dd");
            var yearIndex=formatItems.indexOf("yyyy");
            var month=parseInt(dateItems[monthIndex]);
            month-=1;
            var formatedDate = new Date(dateItems[yearIndex],month,dateItems[dayIndex]);
            return formatedDate;
}

stringToDate("17/9/2014","dd/MM/yyyy","/");
stringToDate("9/17/2014","mm/dd/yyyy","/")
stringToDate("9-17-2014","mm-dd-yyyy","-")

回复于 2024-04-27T01:10:38+08:00

var a = "13:15"
var b = toDate(a, "h:m")
alert(b);

function toDate(dStr, format) {
  var now = new Date();
  if (format == "h:m") {
    now.setHours(dStr.substr(0, dStr.indexOf(":")));
    now.setMinutes(dStr.substr(dStr.indexOf(":") + 1));
    now.setSeconds(0);
    return now;
  } else
    return "Invalid Format";
}

回复于 2024-04-27T01:10:38+08:00

转换为pt-BR格式：

var dateString = "13/10/2014";
    var dataSplit = dateString.split('/');
    var dateConverted;

    if (dataSplit[2].split(" ").length > 1) {

        var hora = dataSplit[2].split(" ")[1].split(':');
        dataSplit[2] = dataSplit[2].split(" ")[0];
        dateConverted = new Date(dataSplit[2], dataSplit[1]-1, dataSplit[0], hora[0], hora[1]);

    } else {
        dateConverted = new Date(dataSplit[2], dataSplit[1] - 1, dataSplit[0]);
    }

我希望能帮到别人！

回复于 2024-04-27T01:10:38+08:00

15
将它作为参数传递给Date（）：
```
var st = "date in some format"
var dt = new Date(st);
```
您可以使用例如： dt.getMonth() 来访问日期，月份和年份 .
回复于 2024-04-27T01:10:38+08:00

还有另一种方法：

String.prototype.toDate = function(format) {
    format = format || "dmy";
    var separator = this.match(/[^0-9]/)[0];
    var components = this.split(separator);
    var day, month, year;
    for (var key in format) {
        var fmt_value = format[key];
        var value = components[key];
        switch (fmt_value) {
            case "d":
                day = parseInt(value);
                break;
            case "m":
                month = parseInt(value)-1;
                break;
            case "y":
                year = parseInt(value);
        }
    }
    return new Date(year, month, day);
};
a = "3/2/2017";
console.log(a.toDate("dmy"));
// Date 2017-02-03T00:00:00.000Z

回复于 2024-04-27T01:10:38+08:00

你可以试试这个：

function formatDate(userDOB) {
  const dob = new Date(userDOB);

  const monthNames = [
    'January', 'February', 'March',
    'April', 'May', 'June', 'July',
    'August', 'September', 'October',
    'November', 'December'
  ];

  const day = dob.getDate();
  const monthIndex = dob.getMonth();
  const year = dob.getFullYear();

  // return day + ' ' + monthNames[monthIndex] + ' ' + year;
  return `${day} ${monthNames[monthIndex]} ${year}`;
}

console.log(formatDate('1982-08-10'));

回复于 2024-04-27T01:10:38+08:00

2
我为此创建了一个小提琴，您可以在任何日期字符串上使用toDate（）函数并提供日期格式 . 这将返回Date对象 . https://jsfiddle.net/Sushil231088/q56yd0rp/
```
"17/9/2014".toDate("dd/MM/yyyy", "/")
```
回复于 2024-04-27T01:10:38+08:00

var st = "26.04.2013";
var pattern = /(\d{2})\.(\d{2})\.(\d{4})/;
var dt = new Date(st.replace(pattern,'$3-$2-$1'));

输出将是：

dt => Date {Fri Apr 26 2013}

回复于 2024-04-27T01:10:38+08:00

在JavaScript中将字符串转换为日期

30 回答

时间戳应该转换为数字

相关问题