Java中DateTime对象之间的小数天数

3 回答

• 0

  如果你使用Hours.hoursBetween，你可能会因为四舍五入而错过几分钟 .

  试试这个：（end.getMillis - start.getMillis（））/（1000 * 3600 * 24）

  回复于 2024-04-25T09:53:30+08:00
• 1

  以毫克为单位减去时间并除以每天的毫秒数：

  double diff = (end.getMillis() - start.getMillis()) / 86400000d;
  

  测试

  DateTime start = new DateTime(2015, 1, 1,  0,  0,  0,   0); // Jan 1, 2015
  DateTime end   = new DateTime(2015, 7, 4, 14, 23, 55, 876); // Jul 4, 2015 at 2:23:55.876 PM
  
  final int MILLIS_PER_DAY = 24 * 60 * 60 * 1000; // 86_400_000
  double diff = (double)(end.getMillis() - start.getMillis()) / MILLIS_PER_DAY;
  System.out.println(diff);
  
  int days = (int)diff;
  diff = (diff - days) * 24;
  int hours = (int)diff;
  diff = (diff - hours) * 60;
  int minutes = (int)diff;
  diff = (diff - minutes) * 60;
  int seconds = (int)diff;
  diff = (diff - seconds) * 1000;
  int millis = (int)Math.round(diff);
  System.out.println(days    + " days, "    +
                     hours   + " hours, "   +
                     minutes + " minutes, " +
                     seconds + " seconds, " +
                     millis  + " millis");
  

  产量

  184.55828560185185
  184 days, 13 hours, 23 minutes, 55 seconds, 876 millis
  

  请注意，由于夏令时，它只有13个小时，而不是14个小时 .

  回复于 2024-04-25T09:53:30+08:00
• 0

  感谢评论的输入，我使用它精确地工作到秒：

  double days = Seconds.secondsBetween(start, end).getSeconds()/86400;
  

  回复于 2024-04-25T09:53:30+08:00