如何定义一个有3个点的平面，并将其绘制成3D？

1 回答

• 1

  您可以使用法线和点向量定义平面 . 要查找法线，可以计算由这三个点定义的两个向量的叉积 .

  然后使用此法线和其中一个点将平面放置在空间中 .

  使用matplotlib：

  import numpy as np
  import matplotlib.pyplot as plt
  from mpl_toolkits.mplot3d import Axes3D
  
  points = [[0.65612, 0.53440, 0.24175],
             [0.62279, 0.51946, 0.25744],
             [0.61216, 0.53959, 0.26394]]
  
  p0, p1, p2 = points
  x0, y0, z0 = p0
  x1, y1, z1 = p1
  x2, y2, z2 = p2
  
  ux, uy, uz = u = [x1-x0, y1-y0, z1-z0]
  vx, vy, vz = v = [x2-x0, y2-y0, z2-z0]
  
  u_cross_v = [uy*vz-uz*vy, uz*vx-ux*vz, ux*vy-uy*vx]
  
  point  = np.array(p0)
  normal = np.array(u_cross_v)
  
  d = -point.dot(normal)
  
  xx, yy = np.meshgrid(range(10), range(10))
  
  z = (-normal[0] * xx - normal[1] * yy - d) * 1. / normal[2]
  
  # plot the surface
  plt3d = plt.figure().gca(projection='3d')
  plt3d.plot_surface(xx, yy, z)
  plt.show()
  

  其他有用的答案：
  Matplotlib - Plot a plane and points in 3D simultaneously
  Plot a plane based on a normal vector and a point in Matlab or matplotlib

  回复于 2024-04-25T16:29:44+08:00