这个GraphQL查询我做错了什么？-Java 学习之路

我是GraphQL的新手，我正在尝试进行突变以从我的数据库中删除一篇文章，但我无法弄清楚如何 . 我正在使用Node.js，Mongoose和GraphQL .

这是我的架构上的突变 .

const Mutation = new GraphQLObjectType({
  name: 'Mutation',
  description: 'Articles Mutations',
  fields: () => ({
    remove: {
      type: articleType,
      description: 'Deletes an article by id',
      args: {
        id: {
          type: new GraphQLNonNull(GraphQLString)
        }
      },
      resolve: (value, {id}) => {
        return db.Article.findOneAndRemove({_id: new ObjectId(id)});
      }
    }
  })
});

这是我在调用API删除文章时使用的查询 .

export const DELETE_ARTICLE_QUERY = (id) => (`{
  remove(id: "${id}") {
    id
    author
    content
    published
    tags
    title
    excerpt
  }
}`);

我究竟做错了什么？

我收到了400 Bad Request错误 . 消息：“无法查询字段”删除“类型”突变“ . ”

1 回答

在发出GraphQL请求时，这里的情况是_2643349 . 你没有't specify whether you were seeing any errors, but I' d wager GraphQL返回类似 cannot query field remove on Query 的东西 .

修改DELETE_ARTICLE_QUERY以包含操作：

export const DELETE_ARTICLE_QUERY = (id) => (`mutation {

为调试目的包含操作名称是一个好习惯，所以你也可以说：

export const DELETE_ARTICLE_QUERY = (id) => (`mutation DeleteArticle {

Edit: 根据您提供的错误，听起来架构对象未正确设置 . 它应该看起来像这样：

const schema = new GraphQLSchema({
  query: new GraphQLObjectType({
    name: "WhateverNameYouWantForQuery",
    fields: {
      // each query is a property here
    }
  }),
  mutation: new GraphQLObjectType({
    name: "WhateverNameYouWantForMutation",
    fields: {
      // each mutation is a property here
    }
  }),
});

如果将突变定义为单独的变量（ Mutation ），则可以将突变属性的值作为该变量进行辅助：

const schema = new GraphQLSchema({
  query: new GraphQLObjectType({
    // query props
  }),
  mutation: Mutation
  }),
});

这是一个可以开箱即用的工作示例 . 启动服务器后，您可以在浏览器中转到 http://localhost:3000/graphql 以访问GraphiQL界面并在那里使用潜在的查询/突变 .

const graphqlHTTP = require('express-graphql');
const app = require('express')();
const {
  GraphQLSchema,
  GraphQLObjectType,
  GraphQLNonNull,
  GraphQLString,
  GraphQLList
} = require('graphql');

const articleType = new GraphQLObjectType({
  name: 'Article',
  fields: {
    title: {
      type: GraphQLString,
    },
  },
});

const Mutation = new GraphQLObjectType({
  name: "RootMutationnnnn",
  fields: () => ({
    remove: {
      type: articleType,
      args: {
        id: {
          type: new GraphQLNonNull(GraphQLString)
        }
      },
      resolve: (value, {id}) => {
        return {title: 'Testing a delete'};
      }
    }
  })
});

const schema = new GraphQLSchema({
  query: new GraphQLObjectType({
    name: "RootQueryyyyy",
    fields: {
      articles: {
        type: new GraphQLList(articleType),
        resolve: () => {
          return [{title: 'Test title'}, {title: 'Test title'}];
        }
      }
    }
  }),
  mutation: Mutation
});

const root = {};

app.post('/graphql', graphqlHTTP({
  schema,
  rootValue: root,
  graphiql: false,
}));

app.get('/graphql', graphqlHTTP({
  schema,
  rootValue: root,
  graphiql: true,
}));

app.listen(3000, function(){
  console.log('listening on port 3000');
});

回复于 2024-04-27T00:30:20+08:00

这个GraphQL查询我做错了什么？

1 回答

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