App Exit不按Android App中的后退按钮（Phonegap＆AngularJS）-Java 学习之路

我是使用AngularJs和PhoneGap的App dev的新手，所以我可能在这里做错了（请纠正） . 我的目标是当/ viewInitialDepartments处于活动状态时（即当用户在该视图中时），如果有人在Android中按下BackButton，则退出App . 相关守则如下：

我的 index.html 页面： -

<!DOCTYPE html>
<html>
<meta name="viewport" content="width=device-width,height=device-height,  initial-scale=1.0, maximum-scale=1.0, user-scalable=0" >
<meta http-equiv="x-ua-compatible" content="ie=10">
<meta name="msapplication-tap-highlight" content="no" >
<link rel="stylesheet" href="css/module-reset.css" ><link rel="stylesheet"  href="css/module-grid.css" ><link rel="stylesheet"  href="css/module-all.css" ><link rel="stylesheet"  href="css/module-transitions.css"><link rel="stylesheet"  href="css/module-custom.css" >  <link rel="stylesheet" href="css/styleMenu.min.css">
<title>ad</title>
<script type="text/javascript" src="cordova.js"></script> 
</head>
<body ng-cloak ng-app="askDadaApp">

<div id="mainBodyWrapper">
<div class="page {{ pageClass }}" ng-view></div>
</div>
<script src="js/angular.min.js"></script>
<script src="js/angular-route.js"></script>
<script src="js/angular-animate.js"></script>
<script src="js/angular-touch.js"></script>
<script src="js/ngprogress.min.js"></script>
<link rel="stylesheet"  href="css/ngProgress.css" >
<script src="js/script-controller.js"></script>
</body>
</html>

我的Angular JS Contol页面（ script-controller.js ）： -

var adApp = angular.module('adApp',['ngRoute', 'ngAnimate','ngTouch','ngProgress']);
adApp.config(function($routeProvider,  $locationProvider) {

$routeProvider
.when('/', {templateUrl: 'views/1-setconnection.html',controller: 'setController' })
.when('/viewInitialDepartments', {templateUrl: 'views/2-viewInitialDepartments.html',controller: 'viewInitialDepartmentsController' })
.when('/offLine', { templateUrl: 'views/1-offLine.html',controller:'offLineController'})
});
// CONTROLLERS
adApp.controller('offLineController', function($scope,  $http, $location, $routeParams ) { $scope.pageClass = 'normal';var notOnlineToast = document.getElementById("notOnlineToast");notOnlineToast.style.display="block";
});
adApp.controller('setController', function($scope, $http, $location) {
var typeList = "CHECKCONNECTION";
$http.get("URL/php/fetchData.php?typeList=" + typeList )
.error(function(response) {$location.path('/offLine');
// if not offline then go to Home View (viewInitialDepartments)
$location.path('/viewInitialDepartments');
});
adApp.controller('viewInitialDepartmentsController', function($scope,  $http, $location, $routeParams) {
var typeList = "CHECKCONNECTION";
$http.get("URL/php/fetchData.php?typeList=" + typeList )
.error(function(response) {
$location.path('/offLine');
});
// REST OF THE CODE
});

我的 config.xml 文件有声明：-gap：plugin name = "org.apache.cordova.dialogs"

现在问题是，当用户在/ viewInitialDepartments视图中时，我需要知道如何在Android Phone上按BackButton时退出App . Please help . （其他一切都按预期正常工作 . ）

EDIT - 我想这可以使用document.addEventListener（"deviceready"，onDeviceReady，false）来实现;和document.addEventListener（"backbutton"）但不知道如何在我现在的代码中这样做，以便backButton执行它对所有其他视图的操作，只是在/ viewInitialDepartments视图中使应用程序关闭 .

1 回答

定义全局变量以存储当前路径（视图）名称

var CURRENT_ROUTE;

在路线更改时将值分配给CURRENT_ROUTE

var adApp = angular.module('adApp',['ngRoute', 'ngAnimate','ngTouch','ngProgress']).run([
    '$rootScope',
    function ($rootScope) {
        $rootScope.$on('$routeChangeStart', function (event, next) {
            CURRENT_ROUTE = next;
        });
    }]);

在后退按钮上执行操作

document.addEventListener("backbutton", function(){
   if(CURRENT_ROUTE === yourviewname){
      navigator.app.exitApp(); // exit app
   }
}, false);

回复于 2024-05-04T13:01:24+08:00

App Exit不按Android App中的后退按钮（Phonegap＆AngularJS）

1 回答

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