我试图将特定节点( EN_PLAN_NAME )中的文本与字符串列表进行比较,因此我只能输出包含与这些字符串之一匹配的文本的节点 . 我尝试使用这个类似问题的答案:
How to compare against multiple strings in xslt
INPUT XML
<EligibilityRecords xmlns="http://CDHC_Eligibility_LSDD">
<Eligibility_Detail_Record xmlns="">
<EN_PLAN_NAME>Health Savings Account</EN_PLAN_NAME>
<EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
</Eligibility_Detail_Record>
<Eligibility_Detail_Record xmlns="">
<EN_PLAN_NAME>zzHealth Reimbursement Arrangement</EN_PLAN_NAME>
<EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
</Eligibility_Detail_Record>
<Eligibility_Detail_Record xmlns="">
<EN_PLAN_NAME>Health Reimbursement Arrangement 233</EN_PLAN_NAME>
<EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
</Eligibility_Detail_Record>
<Eligibility_Detail_Record xmlns="">
<EN_PLAN_NAME>HRA</EN_PLAN_NAME>
<EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
</Eligibility_Detail_Record>
<Eligibility_Detail_Record xmlns="">
<EN_PLAN_NAME>BASE HRA</EN_PLAN_NAME>
<EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
</Eligibility_Detail_Record>
<Eligibility_Detail_Record xmlns="">
<EN_PLAN_NAME>FSA</EN_PLAN_NAME>
<EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
</Eligibility_Detail_Record>
</EligibilityRecords>
EXPECTED OUTPUT XML
<EligibilityRecords xmlns="CDHC_Eligibility_LSDD_Internal">
<Eligibility_Detail_Record xmlns="">
<EN_PLAN_NAME>zzHealth Reimbursement Arrangement</EN_PLAN_NAME>
<EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
</Eligibility_Detail_Record>
<Eligibility_Detail_Record xmlns="">
<EN_PLAN_NAME>Health Reimbursement Arrangement 233</EN_PLAN_NAME>
<EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
</Eligibility_Detail_Record>
<Eligibility_Detail_Record xmlns="">
<EN_PLAN_NAME>HRA</EN_PLAN_NAME>
<EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
</Eligibility_Detail_Record>
<Eligibility_Detail_Record xmlns="">
<EN_PLAN_NAME>BASE HRA</EN_PLAN_NAME>
<EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
</Eligibility_Detail_Record>
</EligibilityRecords>
XSLT
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var"
exclude-result-prefixes="msxsl var s0 ns0" version="1.0"
xmlns:s0="CDHC_Eligibility_LSDD"
xmlns:ns0="CDHC_Eligibility_LSDD_Internal">
<xsl:output omit-xml-declaration="yes" method="xml" version="1.0" />
<xsl:param name="HRAPlanNames">
<PlanName>Health Reimbursement Arrangement</PlanName>
<PlanName>HRA</PlanName>
</xsl:param>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/*">
<ns0:EligibilityRecords>
<xsl:for-each select="Eligibility_Detail_Record">
<xsl:if test="contains(EN_PLAN_NAME,msxsl:node-set($HRAPlanNames)/*)">
<Eligibility_Detail_Record>
<xsl:copy-of select="EN_PLAN_NAME"/>
</Eligibility_Detail_Record>
</xsl:if>
</xsl:for-each>
</ns0:EligibilityRecords>
</xsl:template>
</xsl:stylesheet>
XSLT 输出任何 EN_PLAN_NAME ,其文本包含"Health Reimbursement Arrangement"但不输出任何包含"HRA"的节点 . 我做错了.2682528_我做错了 .
2 回答
注意:您可以从两个示例中选择
translate()
. 我在编辑之前复制了你问题的输入 .我现在无法测试msxsl,但试试这个:
如果没有想到在XSLT中硬编码的计划名称(不使用
xsl:param
),请尝试不使用node-set()
的内容:contains()
函数的两个参数的类型必须是字符串 . 您正尝试将它与节点集一起用作第二个参数,并且(在XSLT 1.0中)这将导致仅考虑节点集中的第一个节点 .如果要保留
HRAPlanNames
参数的当前结构,则需要执行以下操作:XSLT 1.0
为了得到预期的结果 .