从LinearLayout获取子元素

5 回答

• 2

  你总是可以这样做：

  LinearLayout layout = setupLayout();
  int count = layout.getChildCount();
  View v = null;
  for(int i=0; i<count; i++) {
      v = layout.getChildAt(i);
      //do something with your child element
  }
  

  回复于 2024-04-25T23:47:20+08:00
• 18

  我认为这可能会有所帮助：findViewWithTag()

  将TAG设置为您添加到布局的每个View，然后像使用ID一样通过TAG获取该View

  回复于 2024-04-25T23:47:20+08:00
• 3

  我会避免从视图的子项中静态地抓取元素 . 它现在可能会起作用，但会使代码难以维护，并且很容易在将来的版本中出现问题 . 如上所述，正确的方法是设置标签并通过标签获取视图 .

  回复于 2024-04-25T23:47:20+08:00
• 79

  你可以这样做 .

  ViewGroup layoutCont= (ViewGroup) findViewById(R.id.linearLayout);
  getAllChildElements(layoutCont);
  public static final void getAllChildElements(ViewGroup layoutCont) {
      if (layoutCont == null) return;
  
      final int mCount = layoutCont.getChildCount();
  
      // Loop through all of the children.
      for (int i = 0; i < mCount; ++i) {
          final View mChild = layoutCont.getChildAt(i);
  
          if (mChild instanceof ViewGroup) {
              // Recursively attempt another ViewGroup.
              setAppFont((ViewGroup) mChild, mFont);
          } else {
              // Set the font if it is a TextView.
  
          }
      }
  }
  

  回复于 2024-04-25T23:47:20+08:00
• 2

  LinearLayout layout = (LinearLayout)findViewById([whatever]);
  for(int i=0;i<layout.getChildCount();i++)
      {
          Button b =  (Button)layout.getChildAt(i)
      }
  

  如果它们都是按钮，否则转换为查看并检查课程

  View v =  (View)layout.getChildAt(i);
  if (v instanceof Button) {
       Button b = (Button) v;
  }
  

  回复于 2024-04-25T23:47:20+08:00