使用find方法搜索值-Java 学习之路

-1

当代码执行此行时，设置r = tbl.Find（what：= mx），如果单元格包含重复的零或任何数字，则重复返回相同的位置 . 例如，如果我有重复的零搜索：它给我结果为V1B，V1B，V1B而不是返回V1B，V2B和V2C . 我认为只有在重复这些 Value 时才会这样做 . 如何修改此代码？

V1   V2   V3

A 1 5 9

B 0 0 0

C 7 8 4

Sub Finder（）Dim tabl As Range，headr As Range，mx As Double Dim r As Range，colr As Range Dim p As Long

With Sheet1

    For p = 1 To 9
        Set tbl =.Range("B3:D5")
        Set headr =.Range("B2:D2")
        Set colr =.Range("A3:A5")
        mx =.Cells(6 + p, 3)
        Set r = tbl.Find(what:=mx)
        v = Intersect(headr, r.EntireColumn).Value
        v = v & " " & Intersect(colr, r.EntireRow).Value
        .Cells(6 + p, 2) = v
    Next p
End with

结束子

1 回答

这是查找单元格块中所有零的典型方法（它将忽略空白！）

Sub ZeroFinder()
    Dim Block As Range, Zero As Long, _
        r As Range, msg As String, st As String
    Set Block = Range("D6:O32")
    Zero = 0
    Set r = Block.Find(What:=Zero, after:=Block(1))
    If r Is Nothing Then
        MsgBox "no zeros"
        Exit Sub
    End If
    msg = r.Address(0, 0)
    st = msg
    Do Until r Is Nothing
        Set r = Block.FindNext(after:=r)
        If r.Address(0, 0) = st Then Exit Do
        msg = msg & vbCrLf & r.Address(0, 0)
    Loop
    MsgBox msg
End Sub

回复于 2024-04-25T20:41:46+08:00

使用find方法搜索值

1 回答

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