比较两个文件内容

4 回答

• 0

  File1 :
  abc.cde.ccd.eed.12345.5678.txt
  abcd.cdde.ccdd.eaed.12346.5688.txt
  aabc.cade.cacd.eaed.13345.5078.txt
  abzc.cdae.ccda.eaed.29345.1678.txt
  abac.cdae.cacd.eead.18145.2678.txt
  aabc.cdve.cncd.ened.19945.2345.txt
  
  
  File2 :
  12345.5678.txt
  29345.1678.txt
  18145.2678.txt
  10111.2222.txt
  
  
  
  #!/bin/bash
  
  if [ -e Both.txt ]
  then
    rm Both.txt
  fi
  
  if [ -e File1.txt ]
  then
    rm File1.txt
  fi
  
  if [ -e File2.txt ]
  then
    rm File2.txt
  fi
  
  while read f2line
  do
    found=0
    while read f1line
    do
      Both=`echo "$f1line" | grep "$f2line"`
      if [ $? -eq 0 ]
      then
        found=1
        echo $Both >> Both.txt
      fi
    done < File1
  if [ $found -eq 0 ]
  then
    echo $f2line >> File2.txt
  fi
  done < File2
  
  sort Both.txt > s_Both.txt
  sort File1 > s_File1
  comm -3 s_File1 s_Both.txt > File1.txt
  rm s_File1
  rm s_Both.txt
  

  输出文件：Both.txt，File1.txt，File2.txt

  回复于 2024-05-05T23:36:34+08:00
• 0

  同时：

  grep -f text2.txt text1.txt
  

  输出：

  abc.cde.ccd.eed.12345.5678.txt
  abzc.cdae.ccda.eaed.29345.1678.txt
  abac.cdae.cacd.eead.18145.2678.txt
  

  ---

  仅在test1.txt中：

  grep -v -f text2.txt text1.txt
  

  输出：

  abcd.cdde.ccdd.eaed.12346.5688.txt
  aabc.cade.cacd.eaed.13345.5078.txt
  aabc.cdve.cncd.ened.19945.2345.txt
  

  ---

  仅在test2.txt中：

  grep -v -f <( grep -Eo '[0-9]+.[0-9]+.txt' text1.txt) text2.txt
  

  输出：

  10111.2222.txt
  

  回复于 2024-05-05T23:36:34+08:00
• 0

  这个公式可以使用GNU Coreutils的 comm 来解决：

  首先排序第二个文件：

  sort -o test2.txt test2.txt;
  

  然后使用命令来显示行：

  # unique to test1.txt
  cut -d '.' -f 1-4 --complement test1.txt | sort | comm -23 - test2.txt
  # unique to test2.txt
  cut -d '.' -f 1-4 --complement test1.txt | sort | comm -13 - test2.txt
  # that appear in both files
  cut -d '.' -f 1-4 --complement test1.txt | sort | comm -12 - test2.txt
  

  Explanation ：

  # 1. Extract all but first four fields from test1.txt
  cut -d '.' -f 1-4 --complement test1.txt
  # 2. Here '-' replaces standard input
  comm -3 - test2.txt
  

  回复于 2024-05-05T23:36:34+08:00
• 3

  以下AWK脚本 script.awk 也可以完成这项工作：

  NR == FNR { lines[++i] = $0 }
  
  NR > FNR { patterns[++j] = $0 }
  
  END {
      for (p_index in patterns)
          for (l_index in lines)
              if (index(lines[l_index], patterns[p_index]) > 0) {
                  lines_match[l_index] = 1
                  patterns_match[p_index] = 1
              }
  
      print "Lines only in first file:"
      for (l_index in lines)
          if (!(l_index in lines_match)) 
              print lines[l_index]
  
      print "Lines only in second file:"
      for (p_index in patterns)
          if (! (p_index in patterns_match)) 
              print patterns[p_index]
  
      print "Lines in both files:"
      for (l_index in lines)
          if (l_index in lines_match)
              print lines[l_index]
  }
  

  它可以如下调用：

  awk -f script.awk test1.txt test2.txt
  

  请注意，脚本不会对两个文件中的数据结构做任何假设 . 它只是假设 test2.txt 中的行是 test1.txt 中行的潜在子串 .

  回复于 2024-05-05T23:36:34+08:00