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package.Class不是Servlet(Tomcat / J2EE)

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我正在使用Apache Tomcat版本制作一个简单的Web应用程序:8.0.36 . 我得到“类foo.Counter不是Servlet”错误 . 我在Servlet类中扩展了HttpServlet并配置了web.xml . 我反复点击'极端'选项 .

package foo;
import java.io.IOException;
import java.util.ArrayList;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class Counter extends HttpServlet{

@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp)
        throws ServletException, IOException {

    String c=req.getParameter("hobby");

    Choices m=new Choices();
    ArrayList l=m.getNames(c);

    req.setAttribute("name", l);

    RequestDispatcher view=req.getRequestDispatcher("BasicCounter.jsp");
    view.forward(req, resp);
}
}

web.xml文件如下:

<?xml version="1.0" encoding="utf-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">

<servlet>
<servlet-name>Counter</servlet-name>
<servlet-class>foo.Counter</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>Counter</servlet-name>
<url-pattern>/HobbyParameter.do</url-pattern>
</servlet-mapping>

</web-app>

HTML文件为(names.html):

<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert title here</title>
</head>
<body>

<form method="POST" action="HobbyParameter.do">
Choose a Hobby:<br>

<select name="hobby" size="1">
<option>horse skiing
<option>extreme
<option>alpine scuba
<option>speed dating
</select>
<br>
<input type="SUBMIT" >

</form>

</body>
</html>

和JSP一样(BasicCounter.jsp):

<%@page import="java.util.ArrayList"%>
<%@page import="java.util.Iterator"%>
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" 
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
The friends who share your hobby of <%= request.getAttribute("hobby") %> are:<br>
<%
ArrayList list= (ArrayList) request.getAttribute("name");
Iterator it=list.iterator();
while(it.hasNext())
{
out.print("<br>"+it.next());    
}
%>
</body>
</html>

错误如下:

严重:为servlet分配异常计数器java.lang.ClassCastException:foo.Counter无法强制转换为org.apache.catalina的org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1102)中的javax.servlet.Servlet .core.StandardWrapper.allocate(StandardWrapper.java:828)org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:135)org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:106) )org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:502)org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:141)org.apache.catalina.valves.ErrorReportValve . 在org.apache上的org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:616)的org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:88)中调用(ErrorReportValve.java:79) .catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:528)org.apache.coyote.http11 . 摘要Http11Processor.process(AbstractHttp11Processor.java:1099)org.apache.coyote.AbstractProtocol $ AbstractConnectionHandler.process(AbstractProtocol.java:670)at org.apache.tomcat.util.net.NioEndpoint $ SocketProcessor.doRun(NioEndpoint.java: 1520)atg.apache.tomcat.util.net.NioEndpoint $ SocketProcessor.run(NioEndpoint.java:1476)at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)at java.util.concurrent.ThreadPoolExecutor $ worker.run(ThreadPoolExecutor.java:617)at org.apache.tomcat.util.threads.TaskThread $ WrappingRunnable.run(TaskThread.java:61)at java.lang.Thread.run(Thread.java:745)

2 回答

  • 0

    在WEB-INF / lib中查找javax.servlet.ServletException.class的实例 . servler.jar或servlet.api.jar的内容应该由容器提供 . 所以你需要将servler.jar放入WEB-INF / lib文件夹并将jar添加到你的项目中 .

  • 0

    看起来你已经为你的战争组装了servlet.jar .

    如果你使用maven,你应该使用范围 provided 用于servlet api

    <dependency>
     <groupId>javax.servlet</groupId>
     <artifactId>javax.servlet-api</artifactId>
     <version>3.0.1</version>
     <scope>provided</scope>
    </dependency>
    

    确保在Tomcat服务器中没有任何servlet jar依赖项,除了它自己的 .

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