是否可以根据从SoapUI接收的响应xml直接通过groovy脚本更新属性文件？

我尝试了以下步骤

def ui = com.eviware.soapui.support.UISupport


def responseAsXml = context.expand( '${Simple Search - Request 1#ResponseAsXml}')
def groovyUtils = new com.eviware.soapui.support.GroovyUtils(context);
def holder = groovyUtils.getXmlHolder(responseAsXml);


def formataddress = holder.getNodeValues("//result//formatted_address");


props = new java.util.Properties();
props.load( new FileInputStream('testProps.properties') );


def  sQA_PROP_LOCATION = props.getProperty('QA_PROP_LOCATION');

基本上我需要更新 abc.property 文件中的 QA_PROP_LOCATION 属性值，并在响应xml中使用 formatted_address 节点值

响应XML如下

<GeocodeResponse>
   <status>OK</status>
   <result>
      <type>locality</type>
      <type>political</type>
      <formatted_address>Rio de Janeiro, Brazil</formatted_address>
      <address_component>
         <long_name>Rio de Janeiro</long_name>
         <short_name>Rio de Janeiro</short_name>
         <type>locality</type>
         <type>political</type>
      </address_component>
      <address_component>
............

干杯

groovy soapui