在我的应用程序Angular2RC5中,我有一个SSN输入,其作用是在用户键入SSN时添加破折号(ex 123-34-3434) . 我正在使用它作为“反应形式”的一部分(那些不是模板形式......) . 我的模板看起来像这样:
<form class="form-horizontal" [formGroup]="form" (ngSubmit)="submit()">
<div class="thumbnail">
<p class="lead">Please enter your <span *ngIf="context==='fr-secondary'">Spouse's </span> Last Name, SSN, Tax Year, and Quarter</p>
//other inputs
<div class="form-group">
<label class="col-sm-2" for="inputSSN">SSN</label>
<div class="col-sm-4">
<ssn-input formControlName="ssn"></ssn-input>
<!--<span class="help-block error" *ngIf="form.controls['ssn'].errors && form.controls['ssn'].errors['required']">required</span>
<span class="help-block error" *ngIf="form.controls['ssn'].errors && form.controls['ssn'].errors['patternError']">Invalid SSN</span>-->
</div>
</div>
</div>
<button type="submit" class="btn btn-primary pull-right">Next</button>
</form>
每当他们点击提交,我们保存数据,然后如果他们已经表明他们已经结婚,我们想要重置表格并为他们的配偶收集数据 .
因此,当我执行 this.form.reset()
时,除了SSN输入(自定义的)之外的所有输入都会重置,并且表单后端的SSN值会重置,但前一个值仍然可供用户看到(这意味着如果它们点击提交,它将作为空字符串提交,即使他们可以看到一个) .
我也尝试过做 this.form.controls['ssn'].setValue('')
并且做同样的事情 . 更改表单上的值,但该值仍显示在页面上 .
这是整个SSN组件:
import { Component, OnInit, forwardRef, Input } from '@angular/core';
import { FormControl, ControlValueAccessor, NG_VALUE_ACCESSOR, NG_VALIDATORS } from '@angular/forms';
export function createSSNPatternValidator() {
return (c: FormControl) => {
let pattern = /\d{9}/;
let err = {
patternError: {
pattern: /\d{3}-\d{2}-\d{4}/
}
};
return (c.value && !c.value.match(pattern) && c.value.length > 0) ? err : null;
};
}
@Component({
selector: 'ssn-input',
template: `
<input type="text" (input)="updateValue($event)" class="form-control" />
`,
providers: [
{ provide: NG_VALUE_ACCESSOR, useExisting: forwardRef(() => SSNInputComponent), multi: true },
{ provide: NG_VALIDATORS, useExisting: forwardRef(() => SSNInputComponent), multi: true }
]
})
export class SSNInputComponent implements ControlValueAccessor, OnInit {
value: string = '';
propagateChange: any = () => {};
validateFn: any = () => {};
ngOnInit() {
this.validateFn = createSSNPatternValidator();
}
writeValue(value) {
if (value) {
this.value = value;
}
}
registerOnChange(fn) {
this.propagateChange = fn;
}
registerOnTouched() {}
updateValue(event) {
let newValue = event.target.value;
newValue = newValue.replace(/\D/g, '').substr(0, 9);
this.value = newValue;
newValue =
newValue.substr(0, 3) + ((newValue.length >= 4) ? ('-' + newValue.substr(3, 2) + ((newValue.length >= 6) ? '-' + newValue.substr(5, 4) : '')) : '');
event.target.value = newValue;
this.propagateChange(this.value);
}
validate(c: FormControl) {
return this.validateFn(c);
}
}
编辑:plunkr
1 回答
如果使用
writeValue
更新了值,则需要将值分配给输入 .这段代码
如果值为
null
,则显式跳过写入,并且您需要将输入绑定到this.value
,以便更新 .Plunker example