iOS联系人如何通过电话号码获取联系人

2 回答

• 20

  您的实施问题是您在每次搜索时访问地址簿 .

  相反，如果您在第一次访问后保留内存中的地址簿内容，则不会达到此高CPU使用率 .

  • 首先在控制器中保存一个lazy var，它将保存地址簿内容：

  lazy var contacts: [CNContact] = {
      let contactStore = CNContactStore()
      let keysToFetch = [
          CNContactFormatter.descriptorForRequiredKeysForStyle(.FullName),
          CNContactEmailAddressesKey,
          CNContactPhoneNumbersKey,
          CNContactImageDataAvailableKey,
          CNContactThumbnailImageDataKey]
  
      // Get all the containers
      var allContainers: [CNContainer] = []
      do {
          allContainers = try contactStore.containersMatchingPredicate(nil)
      } catch {
          print("Error fetching containers")
      }
  
      var results: [CNContact] = []
  
      // Iterate all containers and append their contacts to our results array
      for container in allContainers {
          let fetchPredicate = CNContact.predicateForContactsInContainerWithIdentifier(container.identifier)
  
          do {
               let containerResults = try     contactStore.unifiedContactsMatchingPredicate(fetchPredicate, keysToFetch: keysToFetch)
              results.appendContentsOf(containerResults)
          } catch {
              print("Error fetching results for container")
          }
      }
  
      return results
  }()
  

  • 当您要查找具有特定电话号码的联系人时，请通过内存中阵列进行迭代：

  .

  func searchForContactUsingPhoneNumber(phoneNumber: String) -> [CNContact] {
      var result: [CNContact] = []
  
      for contact in self.contacts {
          if (!contact.phoneNumbers.isEmpty) {
              let phoneNumberToCompareAgainst = phoneNumber.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet).joinWithSeparator("")
              for phoneNumber in contact.phoneNumbers {
                  if let phoneNumberStruct = phoneNumber.value as? CNPhoneNumber {
                      let phoneNumberString = phoneNumberStruct.stringValue
                      let phoneNumberToCompare = phoneNumberString.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet).joinWithSeparator("")
                      if phoneNumberToCompare == phoneNumberToCompareAgainst {
                          result.append(contact)
                      }
                  }
              }
           } 
      }
  
      return result
  }
  

  I tested it with a very big address book, it works smoothly.

  这是整个视图控制器拼凑在一起以供参考 .

  import UIKit
  import Contacts
  
  class ViewController: UIViewController {
  
      lazy var contacts: [CNContact] = {
          let contactStore = CNContactStore()
          let keysToFetch = [
                  CNContactFormatter.descriptorForRequiredKeysForStyle(.FullName),
                  CNContactEmailAddressesKey,
                  CNContactPhoneNumbersKey,
                  CNContactImageDataAvailableKey,
                  CNContactThumbnailImageDataKey]
  
          // Get all the containers
          var allContainers: [CNContainer] = []
          do {
              allContainers = try contactStore.containersMatchingPredicate(nil)
          } catch {
              print("Error fetching containers")
          }
  
          var results: [CNContact] = []
  
          // Iterate all containers and append their contacts to our results array
          for container in allContainers {
              let fetchPredicate = CNContact.predicateForContactsInContainerWithIdentifier(container.identifier)
  
              do {
                  let containerResults = try contactStore.unifiedContactsMatchingPredicate(fetchPredicate, keysToFetch: keysToFetch)
                  results.appendContentsOf(containerResults)
              } catch {
                  print("Error fetching results for container")
              }
          }
  
          return results
      }()
  
      override func viewDidLoad() {
          super.viewDidLoad()
          // Do any additional setup after loading the view, typically from a nib.
  
          let contact = searchForContactUsingPhoneNumber("(555)564-8583")
          print(contact)
      }
  
      override func didReceiveMemoryWarning() {
          super.didReceiveMemoryWarning()
          // Dispose of any resources that can be recreated.
      }
  
      func searchForContactUsingPhoneNumber(phoneNumber: String) -> [CNContact] {
  
          var result: [CNContact] = []
  
          for contact in self.contacts {
              if (!contact.phoneNumbers.isEmpty) {
                  let phoneNumberToCompareAgainst = phoneNumber.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet).joinWithSeparator("")
                  for phoneNumber in contact.phoneNumbers {
                      if let phoneNumberStruct = phoneNumber.value as? CNPhoneNumber {
                          let phoneNumberString = phoneNumberStruct.stringValue
                          let phoneNumberToCompare = phoneNumberString.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet).joinWithSeparator("")
                          if phoneNumberToCompare == phoneNumberToCompareAgainst {
                              result.append(contact)
                          }
                      }
                  }
              }
          }
  
          return result
      }
  }
  

  我使用flohei's answer作为懒惰的var部分 .

  回复于 2024-04-27T07:35:11+08:00
• 1

  SWIFT 4 UPDATE

  1）添加到.plist

  <key>NSContactsUsageDescription</key>
  <string>Our application needs to your contacts</string>
  

  2）如果您没有请求授权

  func requestAccess() {
  
      let store = CNContactStore()
      store.requestAccess(for: .contacts) { granted, error in
          guard granted else {
              DispatchQueue.main.async {
                 self.presentSettingsActionSheet()
              }
              return
          }
      }
  }
  
  func presentSettingsActionSheet() {
      let alert = UIAlertController(title: "Permission to Contacts", message: "This app needs access to contacts in order to ...", preferredStyle: .actionSheet)
      alert.addAction(UIAlertAction(title: "Go to Settings", style: .default) { _ in
          let url = URL(string: UIApplicationOpenSettingsURLString)!
          UIApplication.shared.open(url)
      })
      alert.addAction(UIAlertAction(title: "Cancel", style: .cancel))
      present(alert, animated: true)
  }
  

  2）如果您之前要求，请检查授权状态

  if CNContactStore.authorizationStatus(for: .contacts) == .authorized {
          getContacts()
  
      }
  

  3）致电获取联系人

  var contacts = [CNContact]()
  
      func getContacts(){
  
      let contactStore = CNContactStore()
      let keys = [CNContactGivenNameKey, CNContactFamilyNameKey, CNContactPhoneNumbersKey, CNContactImageDataAvailableKey, CNContactThumbnailImageDataKey]
      let request = CNContactFetchRequest(keysToFetch: keys as [CNKeyDescriptor])
      request.sortOrder = CNContactSortOrder.givenName
  
      do {
          try contactStore.enumerateContacts(with: request) {
              (contact, stop) in
              self.contacts.append(contact)
          }
      }
      catch {
          print("unable to fetch contacts")
      }
  }
  

  4） THIS IS THE FUNCTION TO GET THE CONTACT NAME OR BY NUMBER

  func getNameFromContacts(number: String) -> String {
      var contactFetched : CNContact
      var contactName = ""
      if contacts.count > 0 {
  
          let numberToBeCompared = number.components(separatedBy:CharacterSet.decimalDigits.inverted).joined(separator: "")
          for c in contacts {
              for n in c.phoneNumbers {
                  if let numberRetrived = n.value as? CNPhoneNumber {
                       let numberRetrivedFixed = numberRetrived.stringValue.components(separatedBy:CharacterSet.decimalDigits.inverted).joined(separator: "")
                      if numberRetrivedFixed.elementsEqual(numberToBeCompared){
                          contactName = c.givenName
                          // OR get the contact --> c
                   contactFetched = c
  
                      }
                  }
              }
          }
  
          return contactName
  
      } else {
          return ""
      }
  }
  

  回复于 2024-04-27T07:35:11+08:00