在Django项目中基于CSRF令牌AJAX的帖子
所以我发现了错误，它出现在我的HTML中 . 我刚刚添加 {% csrf_token %} 并且它有效:)感谢助手们！
（我在第一个答案中使用了给我的JS片段，但我仍然得到403 Forbidden错误！）我可能做错了什么？
我最近学习了JS并尝试了以下用于AJAX POST的JS代码，但是我收到403错误 . 做了一些进一步的研究，发现我需要传递一个CSRF令牌 . 我在网上经历了很多教程，但我能找到的唯一解决方案是JQuery，我不知道该语法是如何工作的 . 我需要知道如何通过基于Javascript AJAX的django项目的帖子传递CSRF令牌 . 我的代码是;
var upvoteBtn = document.querySelector('#upvote');
var downvoteBtn = document.querySelector('#downvote');
upvoteBtn.addEventListener('click', jL);
downvoteBtn.addEventListener('click', cL);
function jL(event) {
document.getElementById("upvote").style.display='none';
document.getElementById("downvote").style.display='none';
var http = new XMLHttpRequest ();
var url = 'entered my url here';
var data = 'title=Post%20Title&body=Body';
var method = 'POST';
http.open(method, url, true);
http.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded')
http.setRequestHeader("X-CSRFToken", csrftoken);
http.onreadystatechange = function() {
if (http.readyState === XMLHttpRequest.DONE && http.status === 200){
document.getElementById("first").innerHTML = "this post has been voted";
console.log("upvote given");
}
else if (http.readyState === XMLHttpRequest.DONE && http.status !== 200){
console.log("error!", http.responseText);
}
};
http.send(data);
}
function cL(event){
document.getElementById("upvote").style.display='none';
document.getElementById("downvote").style.display='none';
var http = new XMLHttpRequest ();
var url = 'entered my url here';
var data = 'title=Post%20Title&body=Body';
var method = 'POST';
http.open(method, url, true);
http.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded')
http.setRequestHeader("X-CSRFToken", csrftoken);
http.onreadystatechange = function() {
if (http.readyState === XMLHttpRequest.DONE && http.status === 200){
document.getElementById("first").innerHTML = "got downvoted";
console.log("downvoted!");
}
else if (http.readyState === XMLHttpRequest.DONE && http.status !== 200){
console.log("error!", http.responseText);
}
};
http.send(data);
}
//function for CSRF token
function getCookie(cname) {
var name = cname + "=";
var decodedCookie = decodeURIComponent(document.cookie);
var ca = decodedCookie.split(';');
for(var i = 0; i <ca.length; i++) {
var c = ca[i];
while (c.charAt(0) == ' ') {
c = c.substring(1);
}
if (c.indexOf(name) == 0) {
return c.substring(name.length, c.length);
}
}
return "";
}
var csrftoken = getCookie('csrftoken');
回答(2)
2 years ago
将这段代码添加到JS中：
function getCookie(name) {
var cookieValue = null;
if (document.cookie && document.cookie != '') {
var cookies = document.cookie.split(';');
for (var i = 0; i < cookies.length; i++) {
var cookie = $.trim(cookies[i]);
// Does this cookie string begin with the name we want?
if (cookie.substring(0, name.length + 1) == (name + '=')) {
cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
break;
}
}
}
return cookieValue;
}
function csrfSafeMethod(method) {
// these HTTP methods do not require CSRF protection
return (/^(GET|HEAD|OPTIONS|TRACE)$/.test(method));
}
function sameOrigin(url) {
// test that a given url is a same-origin URL
// url could be relative or scheme relative or absolute
var host = document.location.host; // host + port
var protocol = document.location.protocol;
var sr_origin = '//' + host;
var origin = protocol + sr_origin;
// Allow absolute or scheme relative URLs to same origin
return (url == origin || url.slice(0, origin.length + 1) == origin + '/') ||
(url == sr_origin || url.slice(0, sr_origin.length + 1) == sr_origin + '/') ||
// or any other URL that isn't scheme relative or absolute i.e relative.
!(/^(\/\/|http:|https:).*/.test(url));
}
if (!csrfSafeMethod(http.responseType) && sameOrigin(http.responseUrl)) {
http.setRequestHeader("X-CSRFToken", getCookie('csrftoken'));
}
基本上，您需要将CSRF令牌添加到标头中 . 我找不到我发现这段代码的链接，如果有人知道会很棒的话 .
2 years ago
你需要打电话：
当您准备
xhr请求时 . （在您的示例中xhr被命名为http）你可以从cookie中获取
csrftoken，但为了做到这一点，你需要实现一个getCookie函数 .像这样的东西应该做的伎俩：
更新
在你的代码中，这应该是这样的：