我有一个我正在创建的Android应用程序,我有一个登录页面作为第一个意图 . 然后,这将打开一个tabholder并将用户带到第一个显示webview视图的选项卡 . 该网站是应用程序的重要组成部分,需要用户登录 . 网站和应用程序使用相同的登录脚本运行相同的服务器,因此登录信息是相同的 . 我想使用登录webview中的应用程序时创建的会话,以便当用户进入webview时他们仍然登录 . 我尝试使用共享首选项重新登录webview但不是工作 . 我能够将共享偏好传递给它,但它仍然告诉我我没有登录网站 . 任何关于这个主题的帮助将不胜感激 .
这是我的代码:
用于创建defaultHttpRequest的Connection类,我将在所有类之间传递 .
import java.io.IOException;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
public class Connection1 {
public static HttpClient httpclient = new DefaultHttpClient();
private static HttpPost httpPost;
public Connection1(){
}
public HttpPost getHttpPost(){
return httpPost;
}
public HttpResponse getResponse() throws ClientProtocolException, IOException{
return httpclient.execute(httpPost);
}
public void setEntity(UrlEncodedFormEntity entity){
httpPost.setEntity(entity);
}
public void setHttpPost(String script){
httpPost = new HttpPost(script);
}
}
将显示网站页面的Webapp类:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.message.BasicNameValuePair;
import android.app.Activity;
import android.content.SharedPreferences;
import android.os.Bundle;
import android.webkit.WebView;
import android.webkit.WebViewClient;
public class WebApp extends Activity {
public static final String PREFS_NAME = "myPrefsFile";
private static final String PREFS_USERNAME = "username";
private static final String PREFS_PASSWORD = "password";
String username = "";
String password = "";
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
}
@Override
protected void onResume() {
// TODO Auto-generated method stub
super.onResume();
setContentView(R.layout.webapp);
SharedPreferences pref = getSharedPreferences(PREFS_NAME, MODE_PRIVATE);
username = pref.getString(PREFS_USERNAME, null);
password = pref.getString(PREFS_PASSWORD, null);
System.out.println(username + "-" + password);
postLoginData();
}
public void postLoginData() {
// Create a new HttpClient and Post Header
Connection1 connection = new Connection1();
connection
.setHttpPost("script.php");
try {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("username", username));
nameValuePairs.add(new BasicNameValuePair("password", password));
connection.setEntity(new UrlEncodedFormEntity(nameValuePairs));
String str = inputStreamToString(
connection.getResponse().getEntity().getContent())
.toString();
if (str.toString().equalsIgnoreCase("success")) {
WebView webapp = (WebView) findViewById(R.id.webView1);
webapp.loadUrl("URL");
webapp.setWebViewClient(new WebViewClient());
webapp.getSettings().setJavaScriptEnabled(true);
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
private StringBuilder inputStreamToString(InputStream is) {
String line = "";
StringBuilder total = new StringBuilder();
// Wrap a BufferedReader around the InputStream
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
// Read response until the end
try {
while ((line = rd.readLine()) != null) {
total.append(line);
}
} catch (IOException e) {
e.printStackTrace();
}
// Return full string
return total;
}
}
2 回答
在您的WebView实例上,调用它 .
并覆盖以下方法: