我正在使用http-core-4.3.3开发反向代理，我需要重写url，例如
/ srv001 / curstomer / id必须重写为/ curstomer / id
这是我的代理处理程序
public void handle(
final HttpRequest request,
final HttpResponse response,
final HttpContext context) throws HttpException, IOException {
long start = System.currentTimeMillis();
DefaultBHttpClientConnection outconn = (DefaultBHttpClientConnection) context.getAttribute(ProxyContext.HTTP_OUT_CONN);
context.setAttribute(HttpCoreContext.HTTP_CONNECTION, outconn);
context.setAttribute(HttpCoreContext.HTTP_TARGET_HOST, this.target);
System.out.println(">> Request URI: " + request.getRequestLine().getUri());
// Remove hop-by-hop headers
...
this.httpexecutor.preProcess(request, this.httpproc, context);
final HttpResponse targetResponse = this.httpexecutor.execute(request, outconn, context);
this.httpexecutor.postProcess(response, this.httpproc, context);
// Remove hop-by-hop headers
...
response.setStatusLine(targetResponse.getStatusLine());
response.setHeaders(targetResponse.getAllHeaders());
response.setEntity(targetResponse.getEntity());
System.out.println("<< Response: " + response.getStatusLine());
final boolean keepalive = this.connStrategy.keepAlive(response, context);
context.setAttribute(ProxyContext.HTTP_CONN_KEEPALIVE, new Boolean(keepalive));
long end = System.currentTimeMillis();
System.out.println("-- request took (msec): " + Long.toString(end - start));
}
我曾尝试在请求时重写目标url，但没有设置方法 . 如何重写目标网址？
1 回答
HttpRequest和HttpResponse对象非常便宜 . 使用HttpCore实现代理时，您应始终制作传入消息的副本，而不是传递相同的对象，原因如下：
URI重写为一
处理所谓的逐跳报头是另一种
协议升级/降级，例如客户端支持HTTP / 1.0且源支持HTTP / 1.1或反之亦然 .