如何将akka streams kafka（reactive-kafka）集成到akka http应用程序中？-Java 学习之路

我有一个基本的scala akka http CRUD应用程序 . 请参阅下面的相关课程 .

我只想将实体id和一些数据（作为json）写入Kafka主题，例如，创建/更新实体 .

我正在看http://doc.akka.io/docs/akka-stream-kafka/current/producer.html，但我是scala和akka的新手，并且不确定如何将它集成到我的应用程序中？

例如，从上面的文档中，这是一个写入kafka的生产环境者的例子，所以我认为我需要类似的东西，但是我的应用程序中的行踪应该如何？我可以在创建用户后在我的服务中的create方法中添加另一个 Map 调用吗？

非常感谢！

val done = Source(1 to 100)
  .map(_.toString)
  .map { elem =>
    new ProducerRecord[Array[Byte], String]("topic1", elem)
  }
  .runWith(Producer.plainSink(producerSettings))

或者我需要在Server.scala中的bindAndHandle（）方法中执行类似于https://github.com/hseeberger/accessus的示例吗？

WebServer.scala

object System {

  implicit val system = ActorSystem()
  implicit val dispatcher = system.dispatcher
  implicit val actorMaterializer = ActorMaterializer()

}

object WebServer extends App {

  import System._

  val config = new ApplicationConfig() with ConfigLoader
  ConfigurationFactory.setConfigurationFactory(new LoggingConfFileConfigurationFactory(config.loggingConfig))
  val injector = Guice.createInjector(new MyAppModule(config))
  val routes = injector.getInstance(classOf[Router]).routes
  Http().bindAndHandle(routes, config.httpConfig.interface, config.httpConfig.port)

}

Router.scala

def routes(): Route = {
    post {
      entity(as[User]) { user =>
        val createUser = userService.create(user)
        onSuccess(createUser) {
          case Invalid(y: NonEmptyList[Err]) =>  {
            throw new ValidationException(y)
          }
          case Valid(u: User) => {
              complete(ToResponseMarshallable((StatusCodes.Created, u)))
          }
        }
      }
    } ~
    // More routes here, left out for example  
}

Service.scala

def create(user: User): Future[MaybeValid[User]] = {
    for {
      validating <- userValidation.validateCreate(user)
      result <- validating match {
        case Valid(x: User) =>
          userRepo.create(x)
            .map(dbUser => Valid(UserConverters.fromUserRow(x)))
        case y: DefInvalid =>
          Future{y}
      }
    } yield result
  }

Repo.scala

def create(user: User): Future[User] = {
    mutateDbProvider.db.run(
      userTable returning userTable.map(_.userId)
        into ((user, id) => user.copy(userId = id)) +=
        user.copy(createdDate = Some(Timestamp.valueOf(LocalDateTime.now())))
    )
  }

1 回答

既然你已经从 Entity 编写了 Route 来解组1 User ，我认为你不需要 Producer.plainSink . 相反，我认为Producer.send也会起作用 . 另外，作为附注，抛出异常不是"idiomatic" scala . 所以我改变了无效用户的逻辑：

val producer : KafkaProducer = new KafkaProducer(producerSettings)

val routes : Route = 
  post {
    entity(as[User]) { user =>
      val createUser = userService.create(user)
      onSuccess(createUser) {
        case Invalid(y: NonEmptyList[Err]) =>  
          complete(BadRequest -> "invalid user")
        case Valid(u: User) => { 
          val producerRecord = 
            new ProducerRecord[Array[Byte], String]("topic1",s"""{"userId" : ${u.userId}, "entity" : "User"}""")

          onComplete(producer send producerRecord) { _ =>
            complete(ToResponseMarshallable((StatusCodes.Created, u)))
          }
        }
      }
    }
  }

回复于 2024-04-26T06:05:35+08:00

如何将akka streams kafka（reactive-kafka）集成到akka http应用程序中？

1 回答

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