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任何人都可以解释backBarButtonItem动作是如何被覆盖的？

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1

我回来问过这个问题 . 但还没有解决方案，这是我的方案 .

//RootViewController.m
[self.navigationController pushViewController:view1 Animated:YES];

这是View1.m

UIBarButtonItem *back_of_view2 = [[UIBarButtonItem alloc]initWithTitle:@"Back to RootViewfromview2"
target:self
action:@selector(backClicked:)];
[self.navigationController pushViewController:view2 animated:YES];

这是backClicked方法:(仍在view1.m中）

-(void)backClicked:(UIBarButtonItem *)back_of_view2
{
[self.navigationController popToRootViewController Animated:YES]
}

我能够将view2中的后退按钮作为“返回RootViewfromview2”，但是没有调用backClicked操作，当我点击后面时，我得到了view1，这是默认操作 . 但是，当我在view2.m中设置leftBarButtonItem时

UIBarButtonItem *backtoOne = [[UIBarButtonItem alloc]initWithTitle:@"JumptorootView" style:UIBarButtonItemStyleBordered target:self action:@selector(someMethod:)];

-(void)someMethod:(UIBarButtonItem *)backtoOne  
{
[self.navigationController popToRootViewController animated:YES];
}

现在..，如果我使用leftBarButtonItem ..，Everthing工作正常，但我不会得到后面的箭头..

iphone objective-c uitableview uinavigationcontroller uibarbuttonitem

2 回答

  • 1

    您可以像默认导航栏中显示的后退按钮一样使用图像 . 如果您覆盖导航栏上的后退按钮，就像在上面的代码中那样，那么您将无法获得默认的后退按钮，而是创建一个像后面的图像按钮并将该图像分配给左侧栏按钮项 .

    希望能帮助到你.......

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  • 2

    处理这种情况的最佳方法是 viewController2 通过委托协议发送 viewController1 消息's about to be popped off the navigation stack. In this sample, I' m假设 viewController2 是类 DetailViewController 的实例 .

    @interface DetailViewController : UIViewController
@property (nonatomic, weak) id <DetailViewControllerDelegate> delegate;
@end

@protocol DetailViewControllerDelegate <NSObject>
- (void)detailViewControllerDidFinish:(DetailViewController *)detailViewController
@end

@implementation DetailViewController

@synthesize delegate = _delegate;

- (void)viewWillDisappear:(BOOL)animated
{
    [super viewWillDisappear:animated];

    if ([self isMovingFromParentViewController]) {
        [self.delegate detailViewControllerDidFinish:self];
    }
}

@end
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