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键值对存储和角度迭代

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{
    "ordersList": [{
        "ordersDto": {
            "testMast": {
                "testId": 9,
                "testName": "HIV"
            },
            "sample": {
                "sampleId": 9050
            }
        }
    }, {

        "ordersDto": {
            "testMast": {
                "testId": 1,
                "testName": "VDRL"
            },
            "sample": null
        }
    }, {

        "ordersDto": {
            "testMast": {
                "testId": 11,
                "testName": "HIV1&2"
            },

            "sample": null
        }
    }, {
        "ordersDto": {
            "testMast": {
                "testId": 3,
                "testName": "HCB"
            },

            "sample": {
                "sampleId": 9050
            }
        }
    }, {

        "ordersDto": {
            "testMast": {
                "testId": 10,
                "testName": "HIV 1&2 Test1"
            },

            "sample": {
                "sampleId": 9051
            }
        }

    }]
}

需要在数组中获取非重复的样本ID，

sample Id = 9050, 9051.

此外，我需要为每个样本ID获取测试名称，重复样本ID我需要将testname添加到同一个数组中 .

testName = HIV, HCB // for 9050
testName = HIV 1&2 Test1" // for 9051

如何在一次迭代中填充这两个数组 . 还要根据样本Id值获取testName . 是否存在以角度存储的任何键值对？

曾尝试使用下面的代码，但没有按预期工作 .

if (vm.ordersList== 1) { // incase of one sample Id
                res.push(vm.ordersList[0].ordersDto.testMast.testName.slice(0, 4));
                sampleId.push(angular.copy(vm.ordersList[0].ordersDto.sample.sampleId));
                sampleRcvdDate.push(angular.copy(vm.ordersList[0].ordersDto.sample.sampleRcvdOn));
              } else {
                angular.forEach(vm.ordersList, function(item) { // multiple sample id's
                  if (item.sample != null) {
                      if(item.sample.sampleId != null && sampleId.indexOf(item.sample.sampleId) == -1 ){
                        res.push(item.testMast.testName.slice(0, 4));
                        sampleId.push(angular.copy(item.sample.sampleId));
                        sampleRcvdDate.push(angular.copy(item.sample.sampleRcvdOn));
                      }
                  }
                })
              }
angularjs angularjs-scope

1 回答

  • 2

    sampleIdTestNameMap将sampleId作为键，testName列表作为值 .

    var sampleIdTestNameMap = {};
angular.forEach(vm.ordersList, function(item) {
    if (item.ordersDto.sample != null && item.ordersDto.sample.sampleId != null) {

        if (sampleId.indexOf(item.ordersDto.sample.sampleId) == -1) {
            sampleId.push(angular.copy(item.ordersDto.sample.sampleId));
            sampleIdTestNameMap[item.ordersDto.sample.sampleId] = [item.ordersDto.testMast.testName];
        } else {
            var tempList = [];
            tempList = sampleIdTestNameMap[item.ordersDto.sample.sampleId];
            tempList.push(item.ordersDto.testMast.testName);
            sampleIdTestNameMap[item.ordersDto.sample.sampleId] = tempList;
        }
    }
});
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