这是我在网上找到的代码,用于根据今天的日期获取当前周的所有日期 . 如果日期是月份的开头,例如 Thursday September 01 2016 则从 Thursday 开始一周,并在 Wednesday September 07 2016 结束一周 . 这真让我烦心,因为如果日期是月末; Sunday July 31 2016 然后它将在 Monday 开始并在那周结束 Sunday ,这正是我想要的 .
这可能是重复但我花了一段时间看着类似的问题,我仍然卡住了 .
Edit: 有没有办法根据当前日期返回当前周的所有日期?(如果你有时间,下周还可以吗?)
func formatDate(date: NSDate) -> String {
let format = "EEEE MMMM dd yyyy"
let formatter = NSDateFormatter()
formatter.dateFormat = format
return formatter.stringFromDate(date)
}
// =======================================================================//
// THIS WEEK DATES //
// =======================================================================//
func formattedDaysInThisWeek() -> [String] {
// create calendar
let calendar = NSCalendar(identifier: NSCalendarIdentifierGregorian)!
// today's date
let today = NSDate()
let todayComponent = calendar.components([.Day, .Month, .Year], fromDate: today)
let components = calendar.components([.Weekday], fromDate: today)
// range of dates in this week
let thisWeekDateRange = calendar.rangeOfUnit(.Day, inUnit:.WeekOfMonth, forDate:today)
// date interval from today to beginning of week
let dayInterval = thisWeekDateRange.location - todayComponent.day
print(thisWeekDateRange.location)
print(todayComponent.day)
// date for beginning day of this week, ie. this week's Sunday's date
if components.weekday == 1 {
print("Is a sunday")
let beginningOfWeek = calendar.dateByAddingUnit(.Day, value: -6, toDate: today, options: .MatchNextTime)
var formattedDays: [String] = []
for i in 0 ..< 7 {
let date = calendar.dateByAddingUnit(.Day, value: i, toDate: beginningOfWeek!, options: .MatchNextTime)!
formattedDays.append(formatDate(date))
}
return formattedDays
} else {
print("Not a sunday")
let beginningOfWeek = calendar.dateByAddingUnit(.Day, value: dayInterval, toDate: today, options: .MatchNextTime)
var formattedDays: [String] = []
for i in 1 ..< thisWeekDateRange.length + 1 {
let date = calendar.dateByAddingUnit(.Day, value: i, toDate: beginningOfWeek!, options: .MatchNextTime)!
formattedDays.append(formatDate(date))
}
return formattedDays
}
}
2 回答
我不知道这里是否有一个实际的问题,但我写了一个快速片段,它总能给你本周的星期日:
此解决方案检查当前日期是否为星期一 .
如果 yes ,那就是本周的开始,如果 no ,回到过去的星期一 .
它还使用
formatDate
函数 .