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有条件地计入dplyr

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29

我有一些会员订单数据，我想按订单周汇总 .

这就是数据的样子：

memberorders=data.frame(MemID=c('A','A','B','B','B','C','C','D'),
             week = c(1,2,1,4,5,1,4,1),
             value = c(10,20,10,10,2,5,30,3))

我正在使用dplyr来group_by“MemID”并总结“值”为“周”<= 2和<= 4（看看每个成员在第1-2周和第1-4周订购了多少 . 我目前的代码是：

MemberLTV <- memberorders %>%
group_by(MemID) %>%
summarize(
sum2 = sum(value[week<=2]),
sum4 = sum(value[week<=4]))

我现在尝试在汇总中添加另外两个字段，count2和count4，它们将计算每个条件的实例数（周<= 2且周<= 4） .

所需的输出是：

output  = data.frame(MemID = c('A','B','C','D'),
                 sum2 = c(30,10,5,3),
                 sum4 = c(30,20,35,3),
                 count2 = c(2,1,1,1),
                 count4 = c(2,2,2,1))

我猜这只是sum函数的一个小调整，但是我很难搞清楚它 .

r dplyr

3 回答

  • 3

    尝试

    library(dplyr)
 memberorders %>% 
        group_by(MemID) %>% 
        summarise(sum2= sum(value[week<=2]), sum4= sum(value[week <=4]), 
                  count2=sum(week<=2), count4= sum(week<=4))
    回复于
  • 41

    使用预览创意并保持一致：

    MemberLTV_2 <- memberorders %>%

group_by(MemID) %>%
summarize(

    count2 = length(value[week<=2]),
    count4 = length(value[week<=4]),
    sum2 = sum(value[week<=2]),
    sum4 = sum(value[week<=4])

    )
    回复于
  • 8

    使用 plyr 包可以做到

    ddply(memberorders,.(MemID),
                    summarise, 
                    val1 = sum(value[week<=2]), 
                    val2 = sum(value[week<=4]),
                    val3 = length(value[week<=2]),
                    val4 = length(value[week<=4]))

  MemID val1 val2 val3 val4
1     A   30   30    2    2
2     B   10   20    1    2
3     C    5   35    1    2
4     D    3    3    1    1
    回复于

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