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Dart获取功能值

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我试图通过自己学习Dart，但我来自C，我有点困惑......

我这样做：

import 'dart:io';
import 'dart:async';
import 'dart:convert';

Future <Map>    ft_get_data()
{
    File    data;

    data = new File("data.json");
    return data.exists().then((value) {
        if (!value)
        {
            print("Data does no exist...\nCreating file...");
            data.createSync();
            print("Filling it...");
            data.openWrite().write('{"index":{"content":"Helllo"}}');
            print("Operation finish");
        }
        return (1);
    }).then((value) {
        data.readAsString().then((content){
            return JSON.decode(content);
        }).catchError((e) {
            print("error");
            return (new Map());
        });
    });
}

void    main()
{
    HttpServer.bind('127.0.0.1', 8080).then((server) {
        print("Server is lauching... $server");
        server.listen((HttpRequest request) {
            request.response.statusCode = HttpStatus.ACCEPTED;
            ft_get_data().then((data_map) {
                if (data_map && data_map.isNotEmpty)
                    request.response.write(data_map['index']['content']);
                else
                    request.response.write('Not work');
            }).whenComplete(request.response.close);
        });
    }) .catchError((error) {
        print("An error : $error.");
    });
}

我正在尝试取回新 Map ，正如你猜测的那样，它不起作用，我得到了“不工作”的信息 . 当代码处于同一功能时，它起作用了......

拜托，你能帮帮我吗？

并且，指针系统为C？

void function(int *i)
{
    *i = 2;
}

int main()
{
    int i = 1;
    function(&i);
    printf("%d", i);
}
// Output is 2.

谢谢您的帮助 .

最终代码：

import 'dart:io';
import 'dart:async';
import 'dart:convert';

Future<Map> ft_get_data()
{
    File    data;

    data = new File("data.json");
    return data.exists()
    .then((value) {
        if (!value) {
            print("Data does no exist...\nCreating file...");
            data.createSync();
            print("Filling it...");
            data.openWrite().write('{"index":{"content":"Helllo"}}');
            print("Operation finish");
        }
    })
    .then((_) => data.readAsString())
    .then((content) => JSON.decode(content))
    .catchError((e) => new Map());
}

void        main()
{
    HttpServer.bind('127.0.0.1', 8080)
    .then((server) {
        print("Server is lauching... $server");
        server.listen((HttpRequest request) {
            request.response.statusCode = HttpStatus.ACCEPTED;
            ft_get_data()
            .then((data_map) {
                if (data_map.isNotEmpty)
                    request.response.write(data_map['index']['content']);
                else
                    request.response.write('Not work');
            })
            .whenComplete(request.response.close);
        });
    })
    .catchError((error) {
        print("An error : $error.");
    });
}
dart dart-async

3 回答

  • 1

    我试图将您的代码重建为"readable"格式 . 我没有测试过，所以可能会有错误 . 对我来说，如果 .then() 没有嵌套，代码就更容易阅读 . 如果 .then() 开始换行，它也有助于阅读 .

    import 'dart:io';
import 'dart:async';
import 'dart:convert';

Future <Map>ft_get_data()
{
    File data;

    data = new File("data.json");
    data.exists() //returns true or false
    .then((value) { // value is true or false
        if (!value) {
            print("Data does no exist...\nCreating file...");
            data.createSync();
            print("Filling it...");
            data.openWrite().write('{"index":{"content":"Helllo"}}');
            print("Operation finish");
        }
    }) // this doesn't need to return anything
    .then((_) => data.readAsString()) // '_' indicates that there is no input value, returns a string. This line can removed if you add return data.readAsString(); to the last line of previous function.
    .then((content) => JSON.decode(content)); // returns decoded string, this is the output of ft_get_data()-function
//    .catchError((e) { //I believe that these errors will show in main-function's error
//      print("error");
//    });
}

void    main()
{
    HttpServer.bind('127.0.0.1', 8080)
    .then((server) {
        print("Server is lauching... $server");
        server.listen((HttpRequest request) {
            request.response.statusCode = HttpStatus.ACCEPTED;
            ft_get_data()
            .then((data_map) {
                if (data_map && data_map.isNotEmpty)
                    request.response.write(data_map['index']['content']);
                else
                    request.response.write('Not work');
            })
            .whenComplete(request.response.close);
        });
    }) 
    .catchError((error) {
        print("An error : $error.");
    });
}
    回复于
  • 1

    你不能插入一个then（）到另一个 . 需要链接它们 . 否则，返回JSON.decode（data）返回到无处（主事件循环）而不是之前的“then”处理程序

    回复于
  • 1

    简要说一下，我会说你需要

    Future<Map> ft_get_data() {
  ...
  return data.exists() ...
  ...
}

    并使用它

    server.listen((HttpRequest request) {
  request.response.statusCode = HttpStatus.ACCEPTED;
  ft_get_data().then((data_map) {
    if (data_map && data_map.isNotEmpty) request.response.write(
        data_map['index']['content']); 
    else 
        request.response.write('Not work');
    request.response.close();
  });
});

    then 内的 return 不会从 ft_get_data 返回，但仅从 then 返回如果涉及异步调用，则可以't continue if it was sync, it'然后异步完全向下 .

    回复于

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