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使用codeigniter为会话数据添加firstname

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我试图弄清楚如何将用户名字添加到会话数据 . 目前我只能添加电子邮件，甚至不知道我是怎么做到的 . 任何帮助将不胜感激，谢谢 .

这是我添加新用户的模型：

public function add_user($key){
        $this->db->where('key', $key);
        $temp_user = $this->db->get('temp_users');

        if($temp_user){
            $row = $temp_user->row();
            $data = array(
                'firstname' => $row->firstname,
                'email' => $row->email,
                'password' => $row->password
            );

            $did_add_user = $this->db->insert('users', $data);
        }
        if($did_add_user){
            $this->db->where('key', $key);
            $this->db->delete('temp_users');
            return $data['email'];
        } return false;

    }

这是我的控制器信息（我当前正在为firstname的会话数据添加一个静态值'kyle'） . 我想添加从数据库中获取的实际用户firstname：

public function register_user($key){
        $this->load->model('model_users');
        if($this->model_users->is_key_valid($key)){
            if($newemail = $this->model_users->add_user($key)){
                $data = array(
                    'firstname' => "kyle",
                    'email' =>  $newemail,
                    'is_logged_in' => 1
                );
                $this->session->set_userdata($data);
                redirect('login/members');
            }else echo "Failed to add user, please try again.";
        }else echo "invalid Key";
    }

这是我的观点：

会员页面

session-> userdata（'email'）; echo $ session_id; ？>

会话级> all_userdata（）;的print_r（$ SESSION_INFO）; ？>

这是会话数组打印出来的内容：

Array ( [session_id] => 4fb01d348ba495ef010fe07415713167 [ip_address] => blah.blah.blah [user_agent] => Mozilla/5.0 (Macintosh; Intel Mac OS X 10_10_1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/39.0.2171.99 Safari/537.36 [last_activity] => 1421942397 [user_data] => [firstname] => kyle [email] => freeride5567@yahoo.com [is_logged_in] => 1 )
php codeigniter session

2 回答

  • 1

    检查codeigniter文档：

    https://www.codeigniter.com/user_guide/libraries/sessions.html

    #1 
public function add_user($key){

    $this->db->where('key', $key);
    $temp_user = $this->db->get('temp_users');

    if($temp_user){
        $row = $temp_user->row();
        $data = array(
            'firstname' => $row->firstname,
            'email' => $row->email,
            'password' => $row->password
        );

       $this->db->insert('users', $data);

       if( $this->db->affected_rows() > 0 ){

          $this->db->where('key', $key);
          $this->db->delete('temp_users');

          return (object)array(
            'email' => $data['email'],
            'firstname' => $data['firstname']  
         );
      } 

    }

    return false;

}

public function register_user($key){
    $this->load->model('model_users');
    if($this->model_users->is_key_valid($key)){
        if($res = $this->model_users->add_user($key)){ //here
            $data = array(
                'firstname' => $res->firstname,
                'email' =>  $res->email,
                'is_logged_in' => 1
            );
            $this->session->set_userdata($data);
            redirect('login/members');
        }else echo "Failed to add user, please try again.";
    }else echo "invalid Key";
}
    回复于
  • 2

    为了通过会话获得名字，tonoslfx的答案是正确的 .

    即：将会话中的数据存储为数组：

    return array(
    'email' => $data['email'],
    'firstname' => $data['firstname']  
);

    根据评论和聊天中的进一步讨论，以下是当用户在注册后登录时如何在会话中获取firstname的解决方案：

    在控制器中：

    public function login_validation(){ 
    $this->load->library('form_validation'); 

    $this->form_validation->set_rules('email', 'Email', 'required|trim|xss_clean|callback_validate_credentials'); 
    $this->form_validation->set_rules('password', 'Password', 'required|md5|trim'); 

    $email = $this->input->post('email');
    $password = $this->input->post('password');

    if($this->form_validation->run()){ 
        if($this->model_users->can_log_in($email, $password)) {
            $userData = $this->model_users->getDataForSession($email);
            $data = array(
                "firstname" => $userData->firstname;
                "email" => $email,
                "is_logged_in" => 1
            );
            $this->session->set_userdata($data);
            redirect('login/members'); 
        }
    } 
    else{ 
        $this->signin(); 
    } 
}

    在'model_users'模型中，使用：

    public function can_log_in($email, $password){
    $this->db->where('email', $email); 
    $this->db->where('password', md5($password)); 
    $query = $this->db->get('users'); 
    if($query->num_rows() == 1){ 
        return true; 
    } 
    else { 
        return false; 
    } 
}

public function getDataForSession($email){
    $this->db->select('firstname');
    $this->db->where('email', $email);
    return $this->db->get('users')->row();
}
    回复于

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