表： ftf
id |名称
表： Ftf_sessions
id | ftfid
表： User
id |用户名|名字|姓氏|电子邮件
表： Ftf_signups
id | sessionid |用户身份
表： Ftf_sessions_dates
id | sessionid |时间开始| timefinish
表： Ftf_signups_status
id | signupid |的StatusCode
你好，
从上面的表格中，我试图生成一个包含如下列的报告：
ftf.name | Ftf_sessions_dates.timestart | Ftf_sessions_dates.timefinish | User.firstname | User.lastname | User.username | User.email | Ftf_signups_status.statuscode
我编写了以下sql查询，它生成报告，除了列ftf.Name
如果有人能指出我正确的方向，我真的很感激 . 我无法在报告中添加列ftf.Name . 谢谢 .
Updated the query and it works now thanks.
select distinct
ftf_signups_status.statuscode as Status,
ftf.name as 'Facetoface Name',
concat(user.firstname, ' ', user.lastname) AS Name,
user.username as Username,
user.email as Email,
DATE_FORMAT( FROM_UNIXTIME( IFNULL( IF( ftf_sessions_dates.timestart <=> 0, NULL,
ftf_sessions_dates.timestart),
ftf_sessions_dates.timestart)), '%M %d, %Y' ) AS StartDate,
DATE_FORMAT( FROM_UNIXTIME( IFNULL( IF( ftf_sessions_dates.timefinish<=> 0, NULL,
ftf_sessions_dates.timefinish),
ftf_sessions_dates.timefinish)), '%M %d, %Y' ) AS FinishDate
from ftf_signups
inner join ftf_signups_status
on ftf_signups.id = ftf_signups_status.signupid
inner join user
on ftf_signups.userid = user.id
inner join ftf_sessions_dates
on ftf_signups.sessionid = ftf_sessions_dates.sessionid
inner join ftf_sessions
on ftf_signups.sessionid = ftf_sessions.id
inner join ftf
on ftf.id = ftf_sessions.facetoface