这没有意义 . Sequelize创建一个以AND而不是WHERE开头的where条件 .
我正在尝试执行此查询:
var query = {
limit: 10,
order: [
['id', 'DESC']
],
//attributes: ['id', 'name', 'supplier_id', 'created_at', 'url'],
include: [
{
required: false,
model: models.termTaxonomies,
include: [{
model: models.term
}, {
attributes: ['id'],
model: models.taxonomy
}],
where: ["termRelationships.product_id IS NULL"],
},
models.image,
models.supplier
],
};
在使用Product.findAll(query)执行上述查询后,在下面创建SQL .
SELECT "product".*
,"termTaxonomies"."id" AS "termTaxonomies.id"
,"termTaxonomies"."taxonomy_id" AS "termTaxonomies.taxonomy_id"
,"termTaxonomies"."term_id" AS "termTaxonomies.term_id"
,"termTaxonomies"."parentId" AS "termTaxonomies.parentId"
,"termTaxonomies"."hierarchyLevel" AS "termTaxonomies.hierarchyLevel"
,"termTaxonomies"."distance" AS "termTaxonomies.distance"
,"termTaxonomies.termRelationships"."product_id" AS "termTaxonomies.termRelationships.product_id"
,"termTaxonomies.termRelationships"."term_taxonomy_id" AS "termTaxonomies.termRelationships.term_taxonomy_id"
,"termTaxonomies.term"."id" AS "termTaxonomies.term.id"
,"termTaxonomies.term"."name" AS "termTaxonomies.term.name"
,"termTaxonomies.term"."plural" AS "termTaxonomies.term.plural"
,"termTaxonomies.term"."sin_article" AS "termTaxonomies.term.sin_article"
,"termTaxonomies.term"."plu_article" AS "termTaxonomies.term.plu_article"
,"termTaxonomies.taxonomy"."id" AS "termTaxonomies.taxonomy.id"
,"images"."id" AS "images.id"
,"images"."deal_id" AS "images.deal_id"
,"images"."image" AS "images.image"
,"supplier"."id" AS "supplier.id"
,"supplier"."name" AS "supplier.name"
,"supplier"."url" AS "supplier.url"
,"supplier"."logo" AS "supplier.logo"
,"supplier"."clicks" AS "supplier.clicks"
,"supplier"."order" AS "supplier.order"
FROM (
SELECT "product"."id"
,"product"."name"
,"product"."subtitle"
,"product"."url"
,"product"."prod_specs"
,"product"."prod_desc"
,"product"."supplier_id"
,"product"."created_at"
,"product"."updated_at"
,"product"."active"
FROM "products" AS "product"
ORDER BY "product"."id" DESC LIMIT 10
) AS "product"
LEFT JOIN (
"term_relationships" AS "termTaxonomies.termRelationships" LEFT JOIN "term_taxonomies" AS "termTaxonomies" ON "termTaxonomies"."id" = "termTaxonomies.termRelationships"."term_taxonomy_id"
) ON "product"."id" = "termTaxonomies.termRelationships"."product_id"
AND termRelationships.product_id IS NULL
LEFT JOIN "terms" AS "termTaxonomies.term" ON "termTaxonomies"."term_id" = "termTaxonomies.term"."id"
LEFT JOIN "taxonomies" AS "termTaxonomies.taxonomy" ON "termTaxonomies"."taxonomy_id" = "termTaxonomies.taxonomy"."id"
LEFT JOIN "images" AS "images" ON "product"."id" = "images"."deal_id"
LEFT JOIN "suppliers" AS "supplier" ON "product"."supplier_id" = "supplier"."id"
ORDER BY "product"."id" DESC;
检查第6行( AND termRelationships.product_id IS NULL
) .
本案例的表格:
我正在尝试将所有产品与他们的供应商和产品一起提供,这些产品尚未归类(因此现在不在termTaxonomies内) .
使用sql查询很容易做到这一点,但现在我们使用的是ORM(Sequelize),我们很乐意完全使用它 . 谁可以帮助我们?
猜猜下面发布我的所有模型有点太多了所以我会尽量保持简短:
协会产品型号:
product.hasMany(_models.offer, {
foreignKey: 'product_id'
});
product.belongsToMany(_models.termTaxonomies, {
through: _models.termRelationships,
foreignKey: 'product_id'
});
product.hasMany(_models.image, {
foreignKey: 'deal_id'
});
product.belongsTo(_models.supplier, {
foreignKey: 'supplier_id'
});
协会提供的模型:
offer.belongsTo(_models.product, {
foreignKey: 'product_id'
});
offer.hasMany(_models.sentDeals, {
foreignKey: 'offer_id'
});
offer.hasMany(_models.transaction, {
foreignKey: 'offer_id'
});
协会供应商型号:
supplier.hasMany(_models.product, {
foreignKey: 'supplier_id'
});
supplier.hasMany(_models.scraperLog, {
foreignKey: 'scraper_id'
});
协会termTaxonomies模型:
termTaxonomies.belongsToMany(_models.product, {
through: _models.termRelationships,
foreignKey: 'term_taxonomy_id',
});
termTaxonomies.belongsTo(_models.term, {
foreignKey: 'term_id',
});
termTaxonomies.belongsTo(_models.taxonomy, {
foreignKey: 'taxonomy_id',
});
1 回答
和是LEFT JOIN的延续: -
LEFT JOIN(“term_relationships”AS“termTaxonomies.termRelationships”LEFT JOIN“term_taxonomies”AS“termTaxonomies”ON“termTaxonomies” . “id”=“termTaxonomies.termRelationships” . “term_taxonomy_id”)ON“product” . “id”=“ termTaxonomies.termRelationships“ . ”product_id“AND termRelationships.product_id IS NULL