我正在尝试在Node.js中的Sequelize中编写belongsToMany关联模型 . 我正在尝试将接收器设备与将要播放的录音相关联 . 一个录音将在许多接收器设备上播放 . 我创建了一个直通表,其中存储关联,其中(范围)子句确保关联类型是“音频”,因为还有其他表使用此关联 .
我 Build 了协会,唯一的问题是我得到了一个
错误:录音与接收器无关!
错误 . 我不确定我哪里出错了,但据我所知,当我定义它们时它们肯定是相关的 .
Definition
var receiver = sequelize.define( 'receiver', {
'id': {
type: Sequelize.BIGINT,
field: 'receiver_id',
allowNull: false,
primaryKey: true,
autoIncrement: true
},
'organizationID': {
type: Sequelize.BIGINT,
field: 'organization_id',
allowNull: false,
validate: {
notEmpty: true
}
},
'identifier': {
type: Sequelize.STRING( 64 ),
field: 'identifier',
allowNull: false,
validate: {
notEmpty: true
}
},
'secret' : {
type: Sequelize.STRING( 64 ),
field: 'secret',
allowNull: false,
validate: {
notEmpty: true
}
},
'iterations' : {
type: Sequelize.INTEGER,
field: 'iterations',
allowNull: false,
validate: {
notEmpty: true
}
},
'sodium': {
type: Sequelize.STRING( 64 ),
field: 'sodium',
allowNull: false,
validate: {
notEmpty: true
}
},
'algorithm' : {
type: Sequelize.STRING( 8 ),
field: 'algorithm',
allowNull: false,
defaultValue: 'sha256'
},
'name' : {
type: Sequelize.STRING( 256 ),
field: 'name',
allowNull: false
}
}, {
'createdAt' : 'created',
'updatedAt' : 'modified',
'deletedAt' : 'deleted',
'tableName' : 'receivers',
'paranoid' : true
} );
var receiverRelation = sequelize.define( 'receiverRelation', {
'receiverID': {
type: Sequelize.BIGINT,
field: 'receiver_id',
allowNull: false,
validate: {
notEmpty: true
}
},
'relationID': {
type: Sequelize.BIGINT,
field: 'relation_id',
allowNull: false,
validate: {
notEmpty: true
}
},
'type': {
type: Sequelize.STRING( 8 ),
field: 'type',
allowNull: false,
validate: {
notEmpty: true
}
}
}, {
'timestamps': false,
'tableName' : 'receiver_relations'
} );
var recording = sequelize.define( 'recording', {
'id': {
type: Sequelize.BIGINT,
field: 'recording_id',
allowNull: false,
primaryKey: true,
autoIncrement: true
},
'receivingComplete' : {
type: Sequelize.BOOLEAN,
field: 'receiving_complete',
allowNull: false,
defaultValue: false
},
'sendingComplete' : {
type: Sequelize.BOOLEAN,
field: 'sending_complete',
allowNull: false,
defaultValue: false
},
'bitrate' : {
type: Sequelize.INTEGER,
field: 'bitrate',
allowNull: false,
defaultValue: false
},
'samplerate' : {
type: Sequelize.INTEGER,
field: 'samplerate',
allowNull: false,
defaultValue: false
},
'channels' : {
type: Sequelize.INTEGER,
field: 'channels',
allowNull: false,
defaultValue: false
},
'format' : {
type: Sequelize.STRING( 8 ),
field: 'format',
allowNull: false,
defaultValue: false
}
}, {
'createdAt' : 'created',
'updatedAt' : 'modified',
'deletedAt' : 'deleted',
'tableName' : 'recordings',
'paranoid' : true
} );
// Recordings to receivers
receiver.belongsToMany( recording,{
'through' : {
'model' : receiverRelation,
'scope' : {
'type' : 'audio'
}
},
'foreignKey' : 'receiver_id',
'as' : 'recording'
} );
recording.belongsToMany( receiver, {
'through' : {
'model' : receiverRelation,
'scope' : {
'type' : 'audio'
}
},
'foreignKey' : 'relation_id',
'as': 'receiver'
} );
Query Code
db.receiver.findAll( {
'include' : [ {
'model' : db.recording,
'where' : { 'id' : recordingRow.get( 'id' ) }
} ]
} )
1 回答
这可能是非常时间的,但错误是'correct',
receiver
和recording
不是 directly 关联,您试图直接获取接收器实例,但是您定义了一个名为receiverRelation
的join table
,因此您需要查询对象,如:我很确定你差不多两年前解决了这个问题,但我想帮忙