我正在尝试创建一个带有关联（天气）的记录（位置）（使用外键插入）以及我尝试的每种方式，我在外键字段 weatherId 中以NULL值结束 .

我在帮助中看到了同时创建主要和次要实体的示例，但在这种情况下，我已经预加载了Weather表，并且用户仅限于从选择列表中选择项目 .

我发现了类似的问题，但没有人回答这个问题 .

Sequelize [Node: 4.2.2, CLI: 2.2.1, ORM: 2.0.0-rc1, mysql: ^2.10.0]

我的模特是： -

位置

'use strict';
module.exports = function(sequelize, DataTypes) {
    var Location = sequelize.define('Location', {
        id: DataTypes.INTEGER,
        locationName: DataTypes.STRING
    }, {
        classMethods: {
            associate: function(models) {
                Location.hasMany(models.Rig);
                Location.belongsTo(models.Weather);
            }
        },
        freezeTableName: true,
        tableName: 'Location',
        timestamps: true
    });
    return Location;
};

MySQL描述了Location

mysql> desc Location;
+--------------+--------------+------+-----+---------+----------------+
| Field        | Type         | Null | Key | Default | Extra          |
+--------------+--------------+------+-----+---------+----------------+
| id           | int(11)      | NO   | PRI | NULL    | auto_increment |
| locationName | varchar(255) | YES  |     | NULL    |                |
| weatherId    | int(11)      | YES  |     | NULL    |                |
| createdAt    | datetime     | NO   |     | NULL    |                |
| updatedAt    | datetime     | NO   |     | NULL    |                |
+--------------+--------------+------+-----+---------+----------------+

天气模型

'use strict';
module.exports = function(sequelize, DataTypes) {
    var Weather = sequelize.define('Weather', {
        id: DataTypes.INTEGER,
        weatherDescription: DataTypes.STRING
    }, {
        classMethods: {
            associate: function(models) {
                Weather.hasMany(models.Location);
            }
        },
        freezeTableName: true,
        tableName: 'Weather',
        timestamps: true
    });
    return Weather;
};

MySQL描述了天气

mysql> desc Weather;
+--------------------+--------------+------+-----+---------+----------------+
| Field              | Type         | Null | Key | Default | Extra          |
+--------------------+--------------+------+-----+---------+----------------+
| id                 | int(11)      | NO   | PRI | NULL    | auto_increment |
| weatherDescription | varchar(255) | YES  |     | NULL    |                |
| createdAt          | datetime     | NO   |     | NULL    |                |
| updatedAt          | datetime     | NO   |     | NULL    |                |
+--------------------+--------------+------+-----+---------+----------------+

首次尝试失败 NULL weatherId

models.Location.create({
    locationName: locationName,
    weatherId: weatherId

}).then(function(location) {
    res.redirect('/location');

}).catch(function(reason) {
    console.log(reason);
});

第二次尝试因 NULL weatherId 而失败

models.Location.create({
    locationName: locationName

}).then(function(location) {
    models.Weather.find({where: { id: weatherId } }).then(function(weather) {
        location.setWeather([weather]).then(function(location) {

            res.redirect('/location');

        }).catch(function(reason) {
            console.log(reason);
        });

    }).catch(function(reason) {
        console.log(reason);
    });

}).catch(function(reason) {
    console.log(reason);
});

然而，当我做更新时，这有用： -

models.Location.find({
    where: {
        id: locationId
    }
}).then(function(location) {
    if (location) {
        location.setWeather([weatherId]).then(function(location) {
            location.updateAttributes({
                locationName: locationName
            }).success(function() {
                res.redirect('/location');
            });
        });
    }
}).catch(function(reason) {
    console.log(reason);
    res.send(reason);
})

日志中没有错误，但仍然 weatherId 是 NULL .

日志中的SQL不包括 weatherId ，如下所示： -

INSERT INTO `Location` (`id`,`locationName`,`createdAt`,`updatedAt`) VALUES (NULL,'test me','2016-01-04 02:33:04','2016-01-04 02:33:04');

任何人都可以帮助我，花了这么多时间在这...

彼得